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HACTEHA [7]
2 years ago
5

2. Four metal mugs with lids each contain the same volume of hot water at the same temperature. The mugs are made from the same

metal and are the same shape and size, but each has its outside surface painted with a different combination of texture and colour.
Which mug radiates thermal energy at the fastest rate?
A the mug painted shiny white
B the mug painted dull white
C the mug painted shiny black
D the mug painted dull black ​
Physics
1 answer:
olga_2 [115]2 years ago
4 0

Answer:

D. the mug painted dull black

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(33%) Problem 3: Two cars collide at an icy intersection and stick together afterward. The first car has a mass of 1100 kg and i
expeople1 [14]

Answer:

The final velocity of the cars is 8.38 m/s at an angle 39.1° south of west.

Explanation:

Given that,

Mass of first car = 1100 kg

Velocity of first car = 8.5 m/s

Mass of second car = 650 kg

Velocity of second car = 17.5 m/s

Suppose we need to find the final velocity of the cars and direction of the cars.

We need to calculate the velocity of the car in west direction

Using conservation of momentum in west direction

m_{f}v_{f}+m_{s}v_{s}= (m_{f}+m_{s})v_{x}

v_{x}=\dfrac{m_{f}v_{f}+m_{s}v_{s}}{(m_{f}+m_{s})}

Put the value into the formula

v_{x}=\dfrac{1100\times0+650\times17.5}{1100+650}

v_{x}=6.5\ m/s

We need to calculate the velocity of the car in south direction

Using conservation of momentum in south direction

m_{f}v_{f}+m_{s}v_{s}= (m_{f}+m_{s})v_{y}

v_{y}=\dfrac{m_{f}v_{f}+m_{s}v_{s}}{(m_{f}+m_{s})}

Put the value into the formula

v_{y}=\dfrac{1100\times8.5+650\times0}{1100+650}

v_{y}=5.3\ m/s

We need to calculate the final velocity of the cars

Using formula of velocity

v_{eq}=\sqrt{(6.5)^2+(5.3)^2}

v_{eq}=8.38\ m/s

We need to calculate the direction

Using formula of direction

\tan\theta=\dfrac{v_{y}}{v_{x}}

Put the value into the formula

\tan\theta=\dfrac{5.3}{6.5}

\theta=\tan^{-1}(\dfrac{5.3}{6.5})

\theta=39.1^{\circ}

Hence, The final velocity of the cars is 8.38 m/s at an angle 39.1° south of west.

8 0
3 years ago
Bob is studying waves in science and learns that the energy of a wave is directly proportional to the square of the waves amplit
Mrrafil [7]
For a simple harmonic motion energy is given with:
E=\frac{1}{2}kA^2
Where k is a constant that depends on the type of the wave you are looking at and A is amplitude.
Let's calculate the energy of the wave using two different amplitudes given in the problem:
E_1=\frac{1}{2}k(1)^2=\frac{1}{2}k\\E_2=\frac{1}{2}k(2)^2=\frac{4}{2}k=2k\\
We can see that energy associated with the wave is 4 times smaller when we decrease its amplitude by half. So the answer should be C.


6 0
3 years ago
Read 2 more answers
A solid sphere of radius 40.0cm has a total positive charge of 26.0μC uniformly distributed throughout its volume. Calculate the
Rudiy27

The magnitude of the electric field for 60 cm is 6.49 × 10^5 N/C

R(radius of the solid sphere)=(60cm)( 1m /100cm)=0.6m

Q\;(\text{total charge of the solid sphere})=(26\;\mathrm{\mu C})\left(\dfrac{1\;\mathrm{C}}{10^6\;\mathrm{\mu C}} \right)={26\times 10^{-6}\;\mathrm{C}}

Since the Gaussian sphere of radius r>R encloses all the charge of the sphere similar to the situation in part (c), we can use Equation (6) to find the magnitude of the electric field:

E=\dfrac{Q}{4\pi\epsilon_0 r^2}

Substitute numerical values:

E&=\dfrac{24\times 10^{-6}}{4\pi (8.8542\times 10^{-12})(0.6)}\\ &={6.49\times 10^5\;\mathrm{N/C}\;\text{directed radially outward}}}

The spherical Gaussian surface is chosen so that it is concentric with the charge distribution.

As an example, consider a charged spherical shell S of negligible thickness, with a uniformly distributed charge Q and radius R. We can use Gauss's law to find the magnitude of the resultant electric field E at a distance r from the center of the charged shell. It is immediately apparent that for a spherical Gaussian surface of radius r < R the enclosed charge is zero: hence the net flux is zero and the magnitude of the electric field on the Gaussian surface is also 0 (by letting QA = 0 in Gauss's law, where QA is the charge enclosed by the Gaussian surface).

Learn more about Gaussian sphere here:

brainly.com/question/2004529

#SPJ4

6 0
2 years ago
Who was the english thinker who established the three laws of motion?.
Tatiana [17]

Answer:

Isaac Newton

Explanation:

Because i learned this in school

4 0
3 years ago
a load of 45 N attached to a spring that is hanging vertically stretches the spring 0.14 m. What is the spring constant?
zhenek [66]
According to Hooke's law, Force = spring constant x displacement of the spring. Spring constant = Force/displacement in spring = 45/0.14 = 321.42 N/m. Hope this helps!
3 0
3 years ago
Read 2 more answers
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