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Triss [41]
3 years ago
8

Answer this question ASAP please and thank you

Physics
2 answers:
allochka39001 [22]3 years ago
8 0
The answer is Oscar Robertson and Jerry West !! hope this helps :p
Flura [38]3 years ago
6 0
Oscar and jerry. Definitely is correct
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Look at the equation shown below. What does the letter Q represent?
Westkost [7]

Answer:

Explanation:

I=CURRENT

Q=CHARGE

t=TIME

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3 years ago
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You are standing on a street corner with your friend. You then travel 14.0 m due west across the street and into your apartment
Margarita [4]

Answer:

Explanation:

We shall express each displacement vectorially , i for each unit displacement towards east , j for northward displacement and k for vertical displacement .

14 m due west = - 14 i

22.0 m upward in the elevator = 22 k

12 m north = 12 j

6.00 m east = 6 i

Total displacement = - 14 i + 22 k + 12 j + 6 i

D = - 8 i + 12 j + 22 k

magnitude = √ ( 8² + 12² + 22² )

= √ ( 64 + 144 + 484 )

= √ 692

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Net displacement from starting point = 26.3 m .

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3 years ago
Suppose a photon with an energy of 1.60 eV strikes a piece of metal. If the electron that it hits loses 0.800 eV leaving the met
JulsSmile [24]

To solve this problem it is necessary to apply the concepts related to the change of Energy in photons and the conservation of energy.

From the theory we could consider that the energy change is subject to

\Delta E = E_0 -W_f

Where

E_0 =Initial Energy

W_f = Energy loses

Replacing we have that

\Delta E = 1.6-0.8

\Delta E = 0.8eV

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3 years ago
A physics major is working to pay her college tuition by performing in a traveling carnival. She rides a motorcycle inside a hol
il63 [147K]

Answer:

v = 12.1 m/s

Explanation:

  • When at the top of the circle, there are two forces acting on the combined mass of the rider and the motorcycle.
  • These are the force of gravity (downward) and the normal force, which is directed from the surface away from it, perpendicular to the surface.
  • In this case, as the motorcycle runs in the interior of the circle, at the top point this force is completely vertical, and is also downward.
  • Since the motorcycle is moving in a vertical circle, there must be a force, keeping the object moving around a circle.
  • This force is the centripetal force, aims towards the center of the circle, and is just the net force aiming in this direction at any point.
  • At the top point, this force is just the sum of the normal force and the weight of the mass of the rider and the motorcycle combined, as follows (we take the direction towards the center as positive):

       F_{c} = N + m*g (1)

  • Now, we know that the centripetal force is related with the tangential speed at this point and the radius of the circle as follows:

       F_{c} = m*\frac{v^{2}}{r} (2)

  • Since the normal force takes any value as needed to make (1) equal to (2),  if the speed diminishes, it will be needed less force to keep the equality valid.
  • In the limit, when the motorcyvle tires barely touch the surface, this normal force becomes zero.
  • In this condition, from (1) and (2), we can find the minimum possible value of  the speed that still keeps the motorcycle touching the surface, as follows:
  • v_{min} =\sqrt{r*g} =\sqrt{15.0m*9.8m/s2} = 12.1 m/s (3)
6 0
3 years ago
A roster lays an egg on top of a barn,the wind is blowing west,which way does the egg roll?
pogonyaev
Hahahahhahaha A ROSTER NEVER LAYS THE EGGS IT IS THE HEN THAT LAYS THE EGGS.....ITS LIKE MEN GETTING PREGNANT LOL
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3 years ago
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