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frosja888 [35]
2 years ago
9

A half litre bottle has a mass of 80g.If contains 500cm3 of liquid when full.The bottle is filled with olive oil of density =0.9

0g/cm3
a. Calculate the mass of oil in the bottle
b. Calculate the mass of the full bottle​
Physics
1 answer:
ELEN [110]2 years ago
7 0

Answer:

See below

Explanation:

a)  500 cm^3  *  .90 gm/cm^3 = 450 gm of oil

b)  450 gm + 80 gm = 530 gm of oil and bottle

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The state of matter depends upon how close the individual particles are together
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Collect information about working of Geyser and prepare a report
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6 0
3 years ago
The downsprue leading into the runner of a certain mold has a length of 175 mm. The cross-sectional area at the base of the spru
adoni [48]

Answer:

(a) Velocity at bottom is 1.85 m/s

(b) Volume flow rate is 7.4 x 10⁻⁴ m³/s.

(c) The time required to fill the mold is 1.35 s.

Explanation:

(a)

Applying Bernoulli's Equation on both ends of the down sprue, with the assumptions that every point is at atmospheric pressure and the liquid metal at the pouring basin is at zero velocity. The equation then becomes:

V = √2gh

where,

V = velocity at bottom of down sprue

h = height of down sprue = 175 mm = 0.175 m

V = √2(9.8 m/s²)(0.175 m)

<u>V = 1.85 m/s</u>

<u></u>

(b)

The volume flow rate is given as:

Volume Flow Rate = (V)(A)

where,

V = velocity at bottom = 1.85 m/s

A = Area of bottom = 400 mm² = 0.0004 m²

Therefore,

Volume Flow Rate = (1.85 m/s)(0.0004 m²)

<u>Volume Flow Rate = 7.4 x 10⁻⁴ m³/s = 740 cm³/s</u>

(c)

The time required to fill the cavity is given as:

Volume Flow Rate = V/t

where,

V = Volume of mold Cavity = 0.001 m³

t = time required to fill the cavity = ?

Therefore,

t = V/Volume Flow Rate

t = 0.001 m³/7.4 x 10⁻⁴ m³/s

<u>t = 1.35 s</u>

<u></u>

5 0
3 years ago
What is the momentum of a 0.000015 kg mosquito flying straight at you with a velocity of 5.20 m/s?
Setler [38]

Answer:

Momentum, p=7.8\times 10^{-5}\ N-m

Explanation:

Given that,

Mass of a mosquito, m = 0.000015 kg

Velocity of the mosquito, v = 5.2 m/s

We need to find the momentum of the mosquito. The momentum of an object is given by :

p = mv

Put all the values in the above formula.

p=0.000015\ kg\times 5.2\ m/s\\\\p=0.000078\ N-m\\\\\text{or}\\\\p=7.8\times 10^{-5}\ N-m

So, the momentum of the mosquito is 7.8\times 10^{-5}\ N-m.

3 0
3 years ago
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