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Ugo [173]
3 years ago
11

A satellite orbiting above the earth needs no power source to keep orbiting the earth. The best explanation for this involves th

e law of inertia. Simply put the law of inertia states A) for every force on an object that object exerts an equal and opposite force back. B) a body in motion will continue in motion unless acted upon by an outside force. C) the net force equals the mass times the acceleration of and object. D) energy cannot be created or destroyed on changed forms.
Physics
2 answers:
lapo4ka [179]3 years ago
6 0
The law of inertia is the second name for Newton's first law of motion, which states that B) a body in motion will continue in motion unless acted upon by an outside force.

The reason that space crafts do not need to be propelled is because there is no frictional force slowing them down as there would be on earth. This means that the craft keeps moving, according to the law of inertia.
Artist 52 [7]3 years ago
6 0

B)

Newton's first law of motion states that a body at rest remains at rest, or, if in motion, remains in motion at a constant velocity unless acted on by a net external force. This is also known as the law of inertia. Inertia is the tendency of an object to remain at rest or remain in motion.Newton's first law of motion states that a body at rest remains at rest, or, if in motion, remains in motion at a constant velocity unless acted on by a net external force. This is also known as the law of inertia. Inertia is the tendency of an object to remain at rest or remain in motion.

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A man drops a rock into a well. (a) the man hears the sound of the splash 2.40 s after he releases the rock from rest. the speed
Burka [1]
Part (a)
Let h =  depth of water surface from the top of the well, m

Because the stone is dropped, its initial velocity is zero.
Let t₁ =  time for the stone to drop, s
Then
h = (1/2)*(9.8 m/s²)*(t₁ s)²
t₁ = √(h/4.9) s = 0.4518√h s

The velocity of sound is 336 m/s.
The time for the sound wave to travel from the water surface to the top of the well is
t₂ = h/336 m/s 

Because the time before the sound is heard is 2.4 s, therefore
t₁ + t₂ = 2.4
0.45181√h + h/336 = 2.4
Multiply through by 336.
151.8082√h + h = 806.4
h - 806.4 = -151.8082√h
h² - 1612.8h + 6.5028 x 10⁵ = 2.3046 x 10⁴h
h² - 2.4659 x 10⁴h + 6.5028 x 10⁵ = 0

Solve with the quadratic formula.
h = 0.5[2.4659 x 10⁴ +/- 2.4606 x 10⁴]
   = 24632 m or 26.5 m

Test the two answers.
When h = 24632,
   t₁ = 0.4518√(24632) = 70.9 s (Not acceptable)
When h = 26.5 m,
   t₁ = 0.4518√(26.5) = 2.3258 s, t₂ = 26.5/336 = 0.0789 s,
   t₁+t₂ = 2.4 s (CORRECT)

Answer:  h = 26.5 m

Part (b)
If travel time for the sound is ignored, then
0.4518√h = 2.4
h = (2.4/0.45118)² = 28.2 m
The percent error is 100*[(28.2 - 26.5)/26.5] = 6.42%

Answer: The error is  6.4%

4 0
3 years ago
If Sherry took her pulse for 6 seconds and felt 14 beats, What would her heart rate be?
Schach [20]

Answer:

140 beats per minute

Explanation:

There are 60 seconds in a minute and we know that Sherry felt 14 beats in 6 seconds if you multiply 6 by 10 you get 60 seconds which can be 1 minute. Then you multiply 14 by 10 since you 14 by 10 since you multiplied 6 by 10 and you get 140 beats per minute.

5 0
3 years ago
Cart 1 of mass m is traveling with speed 2vo in the +x-direction when it has an elastic collision with cart 2 of
iogann1982 [59]

Answer:

Explanation:

Momentum conservation

m2v_0+2mv_0=mv_1+2mv_2 \quad (1/m) \quad 4v_0=v_1+2v_2\\

Kinetic energy conservation

\displaystyle \frac{1}{2}m(2v_0)^2+\frac{1}{2}2mv_0^2=\frac{1}{2}mv_1^2+\frac{1}{2}2mv_2^2 \quad (1/m) \quad 6v_0^2=v_1^2+2v_2^2

Solve the system

6 0
4 years ago
Two hockey pucks, labeled A and B, are initially at rest on asmooth ice surface and are separated by a distance of18.0 m. Simult
zlopas [31]

Answer:

8.505 m

Explanation:

Let V1 and V2 be velocities of puck A and B respectively

Since A and B move in the same direction, so the relative velocity will be V1+V2=3.5+3.9=7.4m/s

Or

Vr=7.4 m/s

Distance=S= 18 m

Time =t=?

S=Vr×t

==> t=S/Vr

==> t= 18/7.4=2.43 sec

At this time both will strike together

<em><u>Distance by puck A</u></em>

<em>V1=3.5 m/s</em>

Time=t= 2.43 sec

Distance covered=d=?

d=V1×t=3.5×2.43=8.505 m

So, puck A will cover 8.505 meters before collision

6 0
3 years ago
Is it true that it takes more energy to vaporize 1 kg of saturated liquid water at 100 C than it would at 120 C?​
Vinvika [58]

Explanation:

Yes, it takes more energy to vaporize 1 kg of saturated liquid water at than it would at .

3 0
2 years ago
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