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denis23 [38]
2 years ago
12

If a crane worker lifts a crate with a mass of 250 kg from the ground to a

Physics
1 answer:
mina [271]2 years ago
7 0

D.

The gravitational of a body is possessed by the body due to the virtue of its position.

The formula for gravitational potential energy is,

                                P.E = mgh joules

Substituting the values

196*9.8*250= 49k

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Please help i'm going to throw up from stress
Eddi Din [679]

Answer:

Explanation:

First of all, I used the specific heat of water as 4182 J/(kgC) and the specific heat of ethyl alcohol (EtOH) as 2440 J/(kgC); that means that we need the masses in kg, not g.

120.g = .1200 kg of ethyl alcohol. Now for the formula:

t_f=\frac{(m_{H2O}*spheat_{H2O}*temp_{H2O})+(m_{EtOH}*spheat_{EtOH}*temp_{EtOH})}{(m_{H2O}*spheat_{H2O})+(m_{EtOH}*spheat_{EtOH})} where spheat is specific heat.

Filling that horrifying-looking formula in with some values:

16.0=\frac{(x*4182*20.0)+(.1200*2440*10.0)}{(x*4182)+(.1200*2440)} and

16.0=\frac{83640x+2928}{4182x+292.8} and

16(4182x + 292.8) = 83640x + 2928 and

66912x + 4684.8 = 83640x + 2928 and

1756.8 = 16728x so

x = .105 kg and the amount of water added is 105 g

4 0
3 years ago
In each case, lifting or pushing, why must you exert a force to move the object? Q1-2: How much more effort is required to lift
musickatia [10]

Answer:

  1. Newton's first law applies. An object at rest will stay that way until a force is applied.
  2. Any amount of effort can be applied to any amount of mass (in the ideal case). The question is not sufficiently specific.

Explanation:

A force is required to move an object because the object will stay at rest until a force is applied.

__

The effort required to lift or push two masses instead of one depends on the desired effect. For the same kinetic energy, no more effort is required. For the same momentum, half the effort is required for two masses. For the same velocity, double the effort is required.

4 0
3 years ago
Find the westward component of a resultant vector 85.42 unit, 23 degrees W of N
Sindrei [870]

Since the angle is West of North, therefore to find for the westward component (horizontal component) of the vector, we use the sin function:

sin θ = opposite side / hypotenuse = westward component / resultant vector

So the westward component (x) is:

x = 85.42 sin 23

<span>x = 33.38 unit</span>

5 0
3 years ago
How long will it take the ball to reach the height of 35m?
Verizon [17]
Ahhh... hello! I’ve done a science experiment that has asked this sort of question. Not as easy as it sounds... I know. I’ll tell you what I learned from that experiment. The answer will depend on the materials the ball is made of and then also your drop length. After these two things are determined, you can get a pretty close time and measurement. I hope this information helps. Have a great night!
~Brooke❤️
7 0
3 years ago
Spiral fracture of bone: Spiral fracture of bone occurs due to twisting of the limb, and is a very common skiing accident. The f
Pavlova-9 [17]

Answer:

principal stresses :б1 = 32.62mPa  б2 = 31.38mPa

Max Shear stress : 16.31 mPa

Orientation of max principle plane = 44.43°

Orientation of minimum principal plane = 134.43°

Explanation:

Given data:

Torque = 50 N-m

weight = 80 kgs

half of weight is subjected to each leg

radius of bone = 10 mm = 0.010 m

<u>a) Determine the principal stresses and shear stress</u>

first calculate the max shear stress ( this will occur in the outermost element

= 16T / π*d^3   where : T = 50 , d = 0.020 m

hence max shear stress = 32 mPa

next determine compressive stress

= ( 40*g)  / π/4*d^2 . where : d = 0.020 m , g = 9.81

hence compressive stress = 1.24 mPa

draw and calculate the radius of Mohr's circle

radius of Mohr's circle = 32.0060

Hence principal stresses = 32.0060 ± 0.62

б1 = 32.62mPa  

б2 = 31.38mPa

attached below is the remaining part of the solution

3 0
3 years ago
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