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cricket20 [7]
2 years ago
5

Equation for solving wavelength

Physics
2 answers:
Lostsunrise [7]2 years ago
8 0
Wavelength= wave speed divided by frequency
Ede4ka [16]2 years ago
7 0

Answer:

The equation for wavelength is λ = v/f

Explanation:

λ is wavelength

v = velocity

f = frequency

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All sound waves move at nearly the same speed through the air.
Genrish500 [490]
High-frequency sound waves have a shorter wavelength and a higher pitch than low-frequency sound waves.
4 0
3 years ago
Read 2 more answers
An electric heater has a Nichrome heating element with a resistance of 9 Ω at 20oC. When 112 V are applied, the electric current
maw [93]

Answer:

975.28 W.

Explanation:

Using,

R' = R(1+αΔt)....................... Equation 1

Where R' = Resistance at the final temperature, R = Resistance at the initial temperature, α = temperature coefficient of resistivity of Nichorome, Δt = Temperature rise.

Given: R = 9 Ω, α = 0.0004/°C, Δt = 1090-20 = 1070 °C

Substitute into equation 1

R' = 9(1+0.0004×1070)

R' = 9(1.428)

R' = 12.862  Ω.

Note: Operating wattage of the heater means the operating power of the heater

The power of the heater is given as,

P = V²/R'...................... Equation 2

Where P = Operating wattage of the heater, V = Voltage, R' = Operating resistance.

Given: V = 112 V, R' = 12.862 Ω

Substitute into equation 2

P = 112²/12.862

P = 975.28 W.

3 0
3 years ago
How much pressure is on the bottom of a pot that holds 20N of soup? the surface area of the pot is 0.05m2
fomenos

Answer:

400

Explanation:

Formula used in solution:

P = \frac{F}{A}

P - pressure,\: F - force,\:  A - area

The given information:

F = 20N

A = 0.05m^{2}

Solution

P = \frac{F}{A} = \frac{20}{0.05} = 20 * 20 = 400

Answer:

Pressure = 400 \: Pascals

8 0
3 years ago
What is a natural form of pollution?
mihalych1998 [28]
Animals peeing and pooping in water which pollutes it

5 0
3 years ago
A nonconducting sphere is made of two layers. The innermost section has a radius of 6.0 cm and a uniform charge density of −5.0C
rosijanka [135]

Answer:

The total charge on the sphere is 46.11 x 10⁻³ C

Explanation:

Given:

charge density of innermost section, σ = −5.0C/m³

radius of the innermost section, r = 6.0cm

charge density of the outer layer ,σ = +8.0 C/m³

radius of the outer layer, r =12.0cm

volume of sphere is given as = \frac{4}{3}.\pi  r^3

Charge enclosed by the innermost section = volume x charge density

volume = \frac{4}{3}\pi  r^3 = \frac{4}{3}\pi  (0.06^3) = 9.05  X 10^{-4} m^3

Enclosed charge, q₁ = −5.0C/m³ X 9.05 x 10⁻⁴ m³

                             = - 4.53 x 10⁻³ C

Charge at the outer surface

Volume =  \frac{4}{3}\pi  [r_2{^3} - r_1{^3}] = \frac{4}{3}\pi  [0.12{^3} - 0.06{^3}] = 0.00633 {m^3}

Enclosed charge, q₂ = +8.0 C/m³ X 0.00633 m³

                            = 50.64 x 10⁻³ C

Total charge on the sphere; Q = q₁ + q₂

                                                   = - 4.53 x 10⁻³ C +  50.64 x 10⁻³ C

                                                   =  46.11 x 10⁻³ C

Therefore, the total charge on the sphere is 46.11 x 10⁻³ C

3 0
3 years ago
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