Answer: This image is the answer to this question.
Explanation:
Answer:
49°C
Explanation:
Let's apply the Ideal Gases Law in order to solve this question:
P . V = n . R . T
Pressure = 1 atm
Volume = 6 L
n = number of moles → 10 g. 1mol /44g = 0.227 moles
R = Ideal Gases Constant
We replace data: 1 atm . 6 L = 0.227 mol . 0.082 . T
6 atm.L / ( 0.227 mol . 0.082) = T
T° = 322 K
We convert T° from K to °C → 322 K - 273 = 49°C
Answer is: cobalt(II) hydroxide.
Ksp(lead(II) chromate) = [Pb²⁺][CrO₄²⁻]. [Pb²⁺] = √2,8·10⁻¹³ = 5,3·10⁻⁷ M.<span>
Ksp(cobalt(II) hydroxide) = </span>[Co²⁺][OH⁻]². [Co²⁺] = ∛1,3·10⁻¹⁵ = 1,1·10⁻⁵ M.
Ksp(cobalt(II) sulfide) = [Co²⁺][S²⁻]. [Co²⁺] = √5·10⁻²² = 2,23·10⁻¹¹ M.
Ksp(chromium(III) hydroxide) = [Cr³⁺][OH⁻]³. [Cr³⁺] = √(√1,6·10⁻³⁰) = 3,6·10⁻⁸.
Ksp(silver sulfide) = [Ag⁺]²[S²⁻].
The correct answer is -2 oxidation state.
Assume that the oxidation number of the sulfur atom in H2S S is x.Now, 2+x=0 ⇒ x=−2. As a result, the oxidation number of sulfur in H2S is -2. Various organosulfur compounds are produced by combining Hydrogen sulfide with sulfur. Sewer gas, swamp gas, stink damp, and sour damp all include Hydrogen sulphide, an invisible gas. It smells strongly of eggs, even in small amounts. It is extremely flammable and poisonous. While drilling for and producing crude oil and natural gas, gases like Hydrogen sulfide (H2S) are regularly found.
learn more about Hydrogen sulfide here:
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