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3 years ago

Describe how you could measure the thickness of paper with an ordinary ruler

1 answer:

5 0

Measure a whole stack (one in which you know the number of sheets), then divide your measurement by the number of sheets in that stack

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A car travels at a speed of 30 mph.How far dose the car travel in 2 hours

Roman55 [17]

Answer:

Car is travelling with 30 m/h.

By unitary method,

1 hour = 30 m

2 hours = 2 × 30 m

Thus car will travel 60 m in 2 hours.

pls give brainliest for the answer

7 0

2 years ago

Do all protostars become stars?

Arada [10]

No not all of them. some can though.

7 0

3 years ago

Read 2 more answers

Space vehicles traveling through Earth's radiation belts can intercept a significant number of electrons. The resulting charge b

Goshia [24]

Answer:

(a) σ = 3.41*10⁻7C/m^2

(b) E = 38,530.1 N/C

Explanation:

(a) In order to calculate the resulting surface charge density, you use the following formula:

$\sigma=\frac{Q}{S}$ (1)

σ: surface charge density

Q: charge of the satellite = 3.1 µC = 3.1*10^-6C

S: surface area of the satellite

The satellite has a spherical form, then, the area of the surface is given by:

$S=4\pi r^2$ (2)

r: radius of the satellite = d/2 = 1.7m/2 = 0.85m

You replace the equation (2) into the equation (1) and solve for the surface charge density:

$\sigma=\frac{3.1*10^{-6}C}{4\pi (0.85m)^2}=3.41*10^{-7}\frac{C}{m^2}$

The surface charge density acquired by the satellite on one orbit is 3.41*10⁻7C/m^2

(b) The electric field just outside the surface is calculate d by using the following formula:

$E=k\frac{Q}{R^2}$ (3)

k: Coulomb's constant = 8.98*10^9 Nm^2/C^2

R: radius of the satellite = 0.85m

$E=(8.98*10^9Nm^2/C^2)\frac{3.1*10^{-6}C}{(0.85m)^2}=38530.1\frac{N}{C}$

The magnitude of the electric field just outside the sphere is 38,530.1 N/C

7 0

3 years ago

At what distance x from the center of the coil, on the axis of the coil, is the magnetic field half its value at the center?

Mrac [35]

Answer:

The value of x is 2.1 cm from the center of the coil.

Explanation:

Radius, R = 2.7 cm

Number of turns, N = 800

The magnetic field at the axis is half of the magnetic field at the center.

$B_{axis}=\frac{B_{center}}{2}\\\\\frac{\mu o}{4\pi}\times \frac{2 \pi I N R^2}{\left (R^2 + x^2 \right )^{\frac{3}{2}}} = 0.5\frac{\mu o}{4\pi}\times\frac{2\pi N I}{R}\\\\\frac{R^2}{(R^2 + x^2)^\frac{3}{2}} = \frac{1}{2R}\\\\4R^6 = (R^2+x^2)^3\\\\1.6 R^2 = R^2 + x^2\\\\x^2 = 0.6 \times 2.7\times 2.7 \\\\x = 2.1 cm$

4 0

3 years ago

people used to think that the sun moved around earth galileo proved this was wrong why is this important

tamaranim1 [39]

To approve to people that the Catholic Church was wrong but they threatened Galileo and he stop

6 0

3 years ago