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d1i1m1o1n [39]
3 years ago
7

Radio waves travel at 3.00 · 108 m/s. Calculate the wavelength of a radio wave of frequency 600 kHz. (6.00 · 105 Hz).

Physics
2 answers:
frutty [35]3 years ago
4 0
Hmm, I got that the wavelength is 500 meters.
stealth61 [152]3 years ago
3 0

Answer:

Wavelength of the radio wave is 500 m.

Explanation:

It is given that,

Speed of radio waves, v=3\times 10^8\ m/s

Frequency of the wave, f=600\ kHz=600\times 10^3\ Hz=6\times 10^5\ Hz

We have to find the wavelength of the radio waves. The wavelength of a wave is given by :

\lambda=\dfrac{v}{f}

\lambda=\dfrac{3\times 10^8\ m/s}{6\times 10^5\ Hz}

\lambda=500\ m

or

\lambda=5\times 10^2\ m

So, the correct option is (d). Hence, this is the required solution.

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Irina-Kira [14]

Answer:

c. 60 m/s

Explanation:

As you can see in the graph, or the description of the graph, the change in speed since the acceleration at 20 seconds was 0 will be all the acceleration that we added up after that second, since we accelerated at 6 m/s until 30 seconds, that means that the object remained 10 seconds accelerating at 6m/s, so 10seconds times 6 m/s that is 60 m/s in the change in speed between the 20th second and the 30th second.

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Dose sound travel faster in a warm room or a cold room? explain your answer
dusya [7]

Answer:Sound travel faster in warm room.

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is the ratio of the specific heats

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8 0
3 years ago
The attractive electrostatic force between the point charges +8.44 ✕ 10-6 and q has a magnitude of 0.961 n when the separation b
d1i1m1o1n [39]
The electrostatic force between two charges Q1 and q is given by
F=k_e  \frac{Q_1 q}{r^2}
where 
ke is the Coulomb's constant
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q is the second charge
r is the distance between the two charges

Re-arranging the formula, we have
q= \frac{F r^2}{k_e Q_1}
and since we know the value of the force F, of the charge Q1 and the distance r between the two charges, we can calculate the value of q:
q= \frac{(0.961 N)(0.67 m)^2}{(8.99 \cdot 10^9 N m^2 C^{-2})(+8.44\cdot 10^{-6}C)}=5.69 \cdot 10^{-6} C

And since the force is attractive, the two charges must have opposite sign, so the charge q must have negative sign.
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