Answer:
v = 7.67 m/s
Explanation:
Given data:
horizontal distance 11.98 m
Acceleration due to gravity 9.8 m/s^2
Assuming initial velocity is zero
we know that
solving for t
we have
substituing all value for time t
t = 1.56 s
we know that speed is given as
v = 7.67 m/s
The problem states that the distance travelled (d) is
directly proportional to the square of time (t^2), therefore we can write this in
the form of:
d = k t^2
where k is the constant of proportionality in furlongs /
s^2
<span>Using the 1st condition where d = 2 furlongs, t
= 2 s, we calculate for the value of k:</span>
2 = k (2)^2
k = 2 / 4
k = 0.5 furlongs / s^2
The equation becomes:
d = 0.5 t^2
Now solving for d when t = 4:
d = 0.5 (4)^2
d = 0.5 * 16
<span>d = 8 furlongs</span>
<span>
</span>
<span>It traveled 8 furlongs for the first 4.0 seconds.</span>
Answer:
<em>10.90km</em>
Explanation:
Magnitude of the total displacement is expressed using the equation
d = √dx²+dy²
dx is the horizontal component of the displacement
dy is the vertical component of the displacement
dy = -6.7sin27°
dy = -6.7(0.4539)
dy = -3.042
For the horizontal component of the displacement
dx = -4.5 - 6.7cos27
dx = -4.5 -5.9697
dx = -10.4697
Get the magnitude of the bicyclist's total displacement
Recall that: d = √dx²+dy²
d = √(-3.042)²+(-10.4697)²
d = √9.2538+109.6146
d = √118.8684
<em>d = 10.90km</em>
<em>Hence the magnitude of the bicyclist's total displacement is 10.90km</em>
<em></em>
Answer:
oxygen
Explanation:
as it is in the air it can't be depleted or used up