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natka813 [3]
3 years ago
13

Describe 2 ways that mass and weight are the same

Physics
1 answer:
navik [9.2K]3 years ago
7 0
Anything that has mass has weight and anything that has weight has mass simple.
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An unmanned aerial vehicle (UAV) (or uncrewed aerial vehicle, commonly known as a drone) is an aircraft without a human pilot on
DaniilM [7]

Answer:

True

Explanation:

  • An unmanned areal vehicle is a device that is capable of flying with an on-board power source, receiver, wing propellers and the flight control board.
  • It functions on the Bernoulli's principle like an airplane does but is controlled remotely by a signal transmitting device with no man on-board.
  • It is used in various fields like construction, farming, remote sensing, defense, videography and aerial photography.

7 0
3 years ago
Write down the role played by four digestive juices in digestion and the
valentinak56 [21]

Answer:

Digestive juices secreted by various organs such as salivary glands in the mouth, stomach, liver and pancreas help in the process of digestion of food. Saliva secreted by the salivary glands in the mouth aids in the breakdown of starch present in the food to simple sugar

Explanation:

3 0
3 years ago
We investigated a jet landing on an aircraft carrier. In a later maneuver, the jet comes in for a landing on solid ground with a
AlexFokin [52]

Answer:

Time  is 14.8 s and cannot landing

Explanation:

This is a kinematic exercise with constant acceleration, we assume that the acceleration of the jet to take off and landing  are the same

Calculate the time to stop, where it has zero speed

       Vf² = Vo² + a t

       t = - Vo² / a

       t = - 110²/(-7.42)

       t = 14.8 s

This is the time it takes to stop the jet

Let's analyze the case of the landing at the small airport, let's look for the distance traveled to land, where the speed is zero

Vf² = Vo² + 2 to X

X = -Vo² / 2 a

X = -110² / 2 (-7.42)

X = 815.4 m

Since this distance is greater than the length of the runway, the jet cannot stop

Let's calculate the speed you should have to stop on a track of this size

Vo² = 2 a X

Vo = √ (2 7.42 800)

Vo = 109 m / s

It is conclusion the jet must lose some speed to land on this track

4 0
3 years ago
A 36.0 kg box initially at rest is pushed 5.00 m along a rough, horizontal floor with a constant applied horizontal force of 130
konstantin123 [22]

Answer:

(a) W = 650J

(b) Wf = 529.2J

(c) W = 0J

(d) W = 0J

(e) ΔK = 120.8J

(f) v2 = 2.58 m/s

Explanation:

(a) In order to find the work done by the applied force you use the following formula:

W=Fd      (1)

F: applied force = 130N

d: distance = 5.0m

W=(130N)(5.0m)=650J

The work done by the applied force is 650J

(b) The increase in the internal energy of the box-floor system is given by the work done of the friction force, which is calculated as follow:

W_f=F_fd=\mu Mgd       (2)

μ: coefficient of friction = 0.300

M: mass of the box = 36.0kg

g: gravitational constant = 9.8 m/s^2

W_f=(0.300)(36.0kg)(9.8m/s^2)(5.0m)=529.2J

The increase in the internal energy is 529.2J

(c) The normal force does not make work on the box because the normal force is perpendicular to the motion of the box.

W = 0J

(d) The same for the work done by the normal force. The work done by the gravitational force is zero because the motion of the box is perpendicular o the direction of the gravitational force.

(e) The change in the kinetic energy is given by the net work on the box. You use the following formula:

\Delta K=W_T         (3)

You calculate the total work:

W_T=Fd-F_fd=(F-F_f)d     (4)

F: applied force = 130N

Ff: friction force

d: distance = 5.00m

The friction force is:

F_f=(0.300)(36.0kg)(9.8m/s^2)=105.84N

Next, you replace the values of all parameters in the equation (4):

W_T=(130N-105.84N)(5.00m)=120.80J

\Delta K=120.80J

The change in the kinetic energy of the box is 120.8J

(e) The final speed of the box is calculated by using the equation (3):

W_T=\frac{1}{2}M(v_2^2-v_1^2)       (5)

v2: final speed of the box

v1: initial speed of the box = 0 m/s

You solve the equation (5) for v2:

v_2 = \sqrt{\frac{2W_T}{M}}=\sqrt{\frac{2(120.8J)}{36.0kg}}=2.58\frac{m}{s}

The final speed of the box is 2.58m/s

5 0
3 years ago
What are the main ideas of physical science
scoray [572]
Physical science is defined as the study of observable phenomena in the universe.<span>The main idea of physical science is known as the "scientific method". </span>

<span>This method states: </span>

<span>1. observe a "real" ( not imaginary ) phenomena. </span>

<span>2. make a hypothesis ( or theory / idea ) that EXPLAINS this phenomena. </span>

<span>3. conduct a real experiment to test this hypothesis. </span>

<span>4. confirm that the experiment validates the original hypothesis and if necessary amend the theory. </span>

<span>This method is responsible for virtually every scientific explanation of every kind. </span><span>It has worked so well that the very communication you are having with me is a result of the wonders of physical science. </span>

<span>Hope your question was answered :)</span>
5 0
3 years ago
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