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Veronika [31]
2 years ago
15

If the empirical formula for a compound is NO2 and the molecular mass is 230.05 g/mol, what is the molecular formula for the com

pound? fast
Chemistry
1 answer:
PilotLPTM [1.2K]2 years ago
5 0

Answer: \text{N}_{5}\text{O}_{10}

Explanation:

  • The atomic mass of nitrogen is 14.0067 g/mol.
  • The atomic mass of oxygen is 15.9994 g/mol.

This means the molecular mass of nitrogen dioxide is 14.0067+2(15.9994)=46.0055 g/mol.

Dividing this molecular mass of the compound we need to find, we get that

\frac{230.05}{46.0055} \approx 5.

So, the final answer is \boxed{\text{N}_{5}\text{O}_{10}}

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What is the empirical formula for c12h24o6? what is the empirical formula for c12h24o6? ch2o cho c2h5o c2h4o cho2?
stira [4]

Empirical formula: The formula consist of proportions of the elements which is present in the compound or the simplest whole number ratios of atoms.

Now, molecular formula is equal to the product of n (ratio) and empirical formula.

Molecular formula = n\times empirical formula    (1)

molecular formula =C_{12}H_{24}O_{6} (given)

Since, 6 is the smallest subscript in above molecular formula to get the simpler whole number of atoms. Therefore, divide all the subscripts i.e. number of carbon atoms (12), number of hydrogen atoms (24) and number of oxygen atoms (6) by 6.

empirical formula becomes C_{2}H_{4}O

Thus, according to the formula (1)

C_{12}H_{24}O_{6} = 6\times C_{2}H_{4}O

Hence, empirical formula of given molecular formula is C_{2}H_{4}O


4 0
3 years ago
Aluminum has a density of 2.70 g/mL. Calculate the mass (in grams) of a piece of aluminum having a volume of 264 mL .
gavmur [86]
The formula for density is:

D = m/v

We can use the formula to figure out the mass because we already know two of the three values (we are given the density and volume), so we only have to solve for <em>m. </em>If we plug our given values into the formula, we get:

2.70 = m / 264

Now, all we need to do is solve for <em>m</em>. The goal is to get <em>m</em> on one side of the equation, and all we have to do is multiply each side of the equation by 264:

264 × 2.70 = (m÷264) × 264

264 × 2.70 = m

m = 712.8

The mass of the piece of aluminum is 712.8 grams.
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