The Heisenberg uncertainty principle listed above states that it’s impossible to determine with high precision both the momentum and position of an electron simultaneously.
Answer:
37.5 mL of a 4.0 M Mg(OH)₂ are needed to make 750 mL of 0.2 M Mg(OH)₂
Explanation:
Dilution is the reduction in concentration of a chemical in a solution. Dilution consists of lowering the amount of solute per unit volume of solution.
In other words, dilution is the procedure followed to prepare a less concentrated solution from a more concentrated one, and consists of adding solvent to an existing solution. The quantity or mass of the solute is not changed but only that of the solvent.
In dilutions the expression is used:
Ci*Vi = Cf*Vf
where:
- Ci: initial concentration
- Vi: initial volume
- Cf: final concentration
- Vf: final volume
In this case:
- Ci: 4 M
- Vi: ?
- Cf: 0.2 M
- Vf: 750 mL
Replacing:
4 M* Vi= 0.2 M* 750 mL
Solving:

Vi= 37.5 mL
<u><em>37.5 mL of a 4.0 M Mg(OH)₂ are needed to make 750 mL of 0.2 M Mg(OH)₂</em></u>
<h3>
Answer:</h3>
22.41 seconds longer
<h3>
Explanation:</h3>
- Sound is a longitudinal wave that requires a material medium for transmission hence called a mechanical wave.
- Examples of medium in which sound travels in are water and air.
From the question give;
Speed of sound in air at 20°C is 343 m/s
Speed of sound in water at 20°C is 1,483 m/s
We are given a distance of 10 Km or 10,000 m
We need to finder how much longer it will take for the sound to travel in air.
Time = Distance ÷ Speed
Therefore;
Time taken in Air = Distance ÷ speed of sound in air
= 10000 m ÷ 343 m/s
= 29.15 seconds
Time taken in water = Distance ÷ speed of sound in water
= 10,000 ÷ 1,483 m/s
= 6.74 seconds
Difference in time = 29.15 seconds - 6.74 seconds
= 22.41 seconds
Therefore, it takes 22.41 seconds longer for sound to travel through air than water.
Answer:
(S)-Pentan-2-ol was treated sequentially with methanesulfonyl chloride (CH3SO2Cl) and then potassium iodide. What is the final product that forms
Explanation:
Alcohols are poor leaving groups.
To make -OH group a better-leaving group, it should be treated with sulfonyl chlorides.
Then, methane sulfonyl group makes will be substituted on the -OH group and forms sulfonyl esters and makes it a better leaving group.
After that treating with KI proceeds through nucleophilic bimolecular substitution and the final product formed is shown below:.