- Calcium carbonate is the salt among the given options.
- Calcium carbonate ( CaCO3) can be regarded as which appears as white and odorless powder or as a colorless crystals it is insoluble in water.
- The chemical formula is CaCO3. It can be used as an antacid as well as food colouring and a food firming agent and a fertilizer.
- Calcium carbonate is calcium salt as well as carbonate salt with one-carbon compound
- Salt can be regarded as substance which is produced by reaction between acid and base. It consists negative ion (anion) of that acid as well as positive ion (cation) of the base.
- Sodium hydroxide is a base and not a salt
- Carbonic acid is an acid and not a salt
- Therefore, calcium carbonate is the only salt in the among the given options.
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Answer:
b) The dehydrated sample absorbed moisture after heating
Explanation:
a) Strong initial heating caused some of the hydrate sample to splatter out.
This will result in a higher percent of water than the real one, because you assume in the calculation that the splattered sample was only water (which in not true).
b) The dehydrated sample absorbed moisture after heating.
Usually inorganic salts may absorbed moisture from the atmosphere so this will explain the 13% difference between calculated water percent the real content of water in the hydrate.
c) The amount of the hydrate sample used was too small.
It will create some errors but they do not create a difference of 13% difference as stated in the problem.
d) The crucible was not heated to constant mass before use.
Here the error is small.
e) Excess heating caused the dehydrated sample to decompose.
Usually the inorganic compounds are stable in the temperature range of this kind of experiments. If you have an organic compound which retain water molecules you may decompose the sample forming volatile compounds which will leave crucible so the error will be quite high.
Answer:
Carbonates (CO3-2), phosphates (PO4-3) and sulfides (S-2) are insoluble.
The exceptions are the alkali metals and the ammonium ion.
Answer:
2 mol H₂O
Explanation:
With the reaction,
- 2H₂(g) + O₂(g) → 2 H₂O(g)
1.55 moles of O₂ would react completely with ( 2*1.55 ) 3.1 moles of H₂. There are not as many moles of H₂, thus H₂ is the limiting reactant.
Now we <u>calculate the moles of H₂O produced</u>, <em>starting from the moles of limiting reactant</em>:
- 2.00 mol H₂ *
= 2 mol H₂O
Answer:
Bleached corals are likely to have reduced growth rates, decreased reproductive capacity, increased susceptibility to diseases and elevated mortality rates. Changes in coral community composition can occur when more susceptible species are killed by bleaching events.
