Answer:
a) 11 m/s
b) 0.0564 s
Explanation:
Given:
m = 2100 kg
vi = 22 ..... m/s before collision
vf = 0 ......after collision to stop
Δs = 0.62 distance traveled after collision .. crumpling of truck
Part a
![V_{avg} = \frac{vi- vf}{2}\\\\V_{avg} = \frac{22- 0}{2}\\\\ V_{avg} = 11 m/s](https://tex.z-dn.net/?f=V_%7Bavg%7D%20%3D%20%5Cfrac%7Bvi-%20vf%7D%7B2%7D%5C%5C%5C%5CV_%7Bavg%7D%20%3D%20%5Cfrac%7B22-%200%7D%7B2%7D%5C%5C%5C%5C%20V_%7Bavg%7D%20%3D%2011%20m%2Fs)
Part b
![vf = vi + a*t\\vf^2 = vi^2 + 2*a*s\\\\0 = 22 + a*t\\t = -22 /a\\\\0 = 484 +2*a*(0.62)\\a = - 390.3232 m/s^2\\\\t = -22/(-390.3232)\\\\t = 0.0564 s](https://tex.z-dn.net/?f=vf%20%3D%20vi%20%2B%20a%2At%5C%5Cvf%5E2%20%3D%20vi%5E2%20%2B%202%2Aa%2As%5C%5C%5C%5C0%20%3D%2022%20%2B%20a%2At%5C%5Ct%20%3D%20-22%20%2Fa%5C%5C%5C%5C0%20%3D%20484%20%2B2%2Aa%2A%280.62%29%5C%5Ca%20%3D%20-%20390.3232%20m%2Fs%5E2%5C%5C%5C%5Ct%20%3D%20-22%2F%28-390.3232%29%5C%5C%5C%5Ct%20%3D%200.0564%20s)
La velocidad correcta de la luz en el vacío es 300.000 km/s .
La distancia = (velocidad) x (duración de tiempo)
Duración de tiempo = 494 segundos, porque cada minuto = 60 segundos
La distancia = (300.000 km/s) x (494 s)
<em>La distancia = 148.200.000 km</em>
Gravity is an attractive force that works to pull objects together. If 2 objects are close the gravitational pull will be stronger
Mass and distance determine gravity. The farther two things are away from each other, the weaker the gravitational forces are, the less mass an object has the less gravitational force it exerts
m =dm ______ 10.000
Meters
The metre is a unit of length in the metric system, and is the base unit of length in the International System of Units (SI).
As the base unit of length in the SI and other m.k.s. systems (based around metres, kilograms and seconds) the metres is used to help derive other units of measurement such as the newton, for force.