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Oksana_A [137]
2 years ago
8

The process of chlorination in water treatment aims at ?​

Chemistry
1 answer:
Andrews [41]2 years ago
8 0

Answer:

Chlorowanie wody jest procesem względnie tanim – koszt zbudowania samej instalacji do dezynfekcji, jak również koszt operacyjny wytworzenia 1 metra sześciennego uzdatnionej chlorem wody jest niższy od dezynfekcji wody za pomocą ozonu. Źródłem chloru w procesie dezynfekcji jest zazwyczaj podchloryn sodu, rzadziej dwutlenek chloru.

Explanation:

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As a team, determine the rules for naming binary ionic compounds that have a "special" transition metal in it when given the for
Lesechka [4]

Answer:

Metal name (charge in roman numerals) Non metal

for example Iron (III) chloride

Explanation:

The rule for naming special transition metal are as follows -

a) First name the transition metal

b) Now write the name of the non metal in the chemical formula.

c) Write the charge for the non metal.

d) If there is a polyatomic ion, write the Common Ion Table ,its formula and charge.

e) Based on the total charge on the non-metal or polyatomic ion, deduce the total charge on the transition metal

f) Write the charge of transition metal after the name of metal in Roman Numeral in parentheses

3 0
2 years ago
How many moles of N2O3 contain 2.55 × 1024 oxygen atoms
Varvara68 [4.7K]
1mol   ------------   3×6,02×10²³ oxygen atoms
x          ------------   2,55×10²⁴

x = 2,5×10²⁴ × 1mol / 3×6,02×10²³ ≈ 0,138*10 mol = 1,38mol

6 0
2 years ago
How many moles are in 13.0 grams of water​
ira [324]

13.0/18=.07222222

sig figs: 0.722 mole of water

6 0
3 years ago
8. 00 g of ethane gas, c2h6, is burned in oxygen. What volume of carbon dioxide gas is produced at 1. 00 atm and 25. 0°c?.
Sonbull [250]

Answer:

Explanation:1 g CH

4

​

,C

2

​

H

6

​

C

3

​

H

8

​

C

4

​

H

10

​

T = 350 K, P = 1 atm

PV=nRT=

M

w×R×T

​

1×V=

58

1

​

×0.0821×350

V=0.495 L

V=495cm

3

8 0
1 year ago
Determine the empirical formula. a 3.880g sample contains 0.691g of magnesium , 1.84 g of sulfur , and 1.365 g of oxygen .
Aliun [14]

Answer:

Mg S2 O3

Explanation:

.691 g of Mg  is .284 mole

1.84 g of S    is .5739 mole

1.365 g of O is  .8531 mole      you can see the ratio is ~  1 :2 :3

                                                        Mg S2 O3

4 0
2 years ago
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