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Sedbober [7]
2 years ago
13

A 75,000-watt radio station transmits at 88 MHz. Determine the number of joules transmitted per second. 88 J/s 8800 J/s 2,000,00

0 J/s 75,000 J/s
Physics
1 answer:
Free_Kalibri [48]2 years ago
6 0

Answer:

the first one is the correct answer

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An apple is held completely submerged just below the surface of water in a container. The apple is then moved to a deeper point
Tresset [83]

Answer:

Explanation:

When the apple is held submerged in water , it experiences a buoyant force due to which it floats in water . One has to apply downward force to keep it submerged. The lower the buoyant force , lower the force needed to submerge it in water.

When apple is held at much deeper point , it experience greater pressure due to column of water around it . So its size or its volume decreases . But its weight remains the same . Due to less volume , buoyant force also decreases ( buoyant force is equal to weight of displaced volume of water. )

Due to buoyant force becoming less , force needed on apple  in downward direction will also be less.

4 0
4 years ago
A rocket sled accelerates from 10 m/s to 40 m/s in 2 seconds. What is the average acceleration of the sled?
Dafna11 [192]

Answer:

15m/s²

Explanation:

Given parameters:

Initial velocity  = 10m/s

Final velocity  = 40m/s

Time taken  = 2s

Unknown:

Average acceleration  = ?

Solution:

Acceleration is the rate of change of velocity with time;

 Acceleration  = \frac{Final velocity   -  Initial velocity }{time}  

  Acceleration = \frac{40 - 10}{2}    = 15m/s²

6 0
3 years ago
_________ = voltage / resistance <br> a. power <br> b. energy <br> c. charge <br> d. current
Fittoniya [83]

c.charge due to the reaction process between the two



4 0
3 years ago
Someone please help me will give BRAILIEST!!!!!
ratelena [41]
The speed increases, because as the angle increases (the wing slants up more steeply), the air has to go farther to get over the wing.
4 0
3 years ago
A 3.00 μF capacitor is charged to 480 V and a 4.00 μF capacitor is charged to 500 V . Part A These capacitors are then disconnec
pogonyaev

Q before connected = Q after connected C1V1+C2V2 = (C1+C2) V

C1= 3×10^-6 F

V1= 480v

C2= 4×10^-6 F

V2= 500v

(3×10^-6)×(480) + (4×10^-6)×(500) = (3×10^-6 + 4×10^-6) × V

Simplifying the above, we get:

( 1440× 10^-6) + (2000 ×10^-6) = (7 × 10^-6) × V.

Further simplified as:

3440 × 10^-6 = 7 × 10^-6 × V

Making V the subject

V = 491.43volts

Therefore the potential difference across each capacitor is 491.43v

4 0
3 years ago
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