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2 years ago

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A 75,000-watt radio station transmits at 88 MHz. Determine the number of joules transmitted per second. 88 J/s 8800 J/s 2,000,00

0 J/s 75,000 J/s

1 answer:

Free_Kalibri [48]2 years ago

6 0

Answer:

the first one is the correct answer

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In science, a broad idea that has been repeatedly verified so as to give scientists great confidence that it represents reality

Colt1911 [192]

In science, a broad idea that has been repeatedly verified so as to give scientists great confidence that it represents reality is called "a theory".

<u>Explanation:</u>

In science, the interpretation of a feature of the organic world that can be tested in repeat manner and analysed by applying agreed tests validation methods, calculation and observation in according to the scientific method, such process is called as a theory in science.

The difference lie between a theory and a hypothesis. Because hypothesis is an "educated guess". Overall it is either a proposed interpretation of an observed phenomenon, or a logical inference of a possible causal association between several phenomena.

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3 years ago

You walk to school every day. It is 0.5 miles. After school you walk to Kroger, which is 1.3 miles. You leave Kroger to go all b

marin [14]

The total distance you haved walked should be 2.6 miles

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2 years ago

A wire of length 5mm and Diameter 2m extends by 0.25 when a force of 50N was use. calculate the

bazaltina [42]

Answer and Explanation:

Data provided in the question

Force = 50N

Length = 5mm

diameter = 2.0m = $2\times 10^{-3}$

Extended by = 0.25mm = $0.25\times 10^{-3}$

Based on the above information, the calculation is as follows

a. The Stress of the wire is

$= \frac{force\ applied}{area\ of \ circle}$

here area of circle = perpendicular to the are i.e cross-sectional i.e

= $\frac{\pi d^{2}}{4}$

= $\frac{\pi(2\times 10^{-3})^2}{4}$

Now place these above values to the above formula

$= \frac{4\times 50}{\pi\times 4 \times 10^{-6}} \\\\ = \frac{50}{\pi}$

= 15.92 MPa

As 1Pa = 1 by N m^2

So,

MPa = 10^6 N m^2

b. Now the strain of the wire is

$= \frac{Change\ in\ length}{initial\ length} \\\\ = \frac{0.25\times 10^{-3}}{5}$

= $5 \times 10^{-5}$

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3 years ago

Two trains A and B of length 400 m each are moving on two parallel tracks with

Vinvika [58]

<u>Answer:</u>

<em>The initial distance between the trains is 1450 m. </em>

<u>Explanation:</u>

In the question two trains are of equal length 400 m and moves at a uniform speed of 72 km/h. train A is moving ahead of train B. If the train B has to overtake train A it should accelerate.

Train B’s acceleration is $1m/s^2$ and it accelerated for 50 seconds.

<em> $a=1 m/s^2$ </em>

<em>t=50 s </em>

<em>initial speed u=72km/h </em>

<em>we have to convert this speed into m/s </em>

<em> $u=72 \times 5/18=20 m/s$ </em>

<em>Distance covered in accelerating phase $S=ut+1/2 at^2$ </em>

<em> $=20 \times 50+1/2 \times 1 \times 50^2$ </em>

<em> $=1000+1250=2250 m$ </em>

If a train is just behind another, the distance covered by the train located behind during overtaking phase will be equal to the sum of the lengths of the trains.

<em>Here length of train A+length of train $B=400+400=800 m$ </em>

<em>Hence the initial distance between the trains = $2250-800=1450 m$ </em>

6 0

3 years ago

Test populations are studied. Population one is found to obey the differential equation dy1/da=o.2y1 and the population two obey

oksano4ka [1.4K]

Answer:

Population 1 indicates growth while Population 2 indicates a declining population

Explanation:

Here, using the given rate of change of the population, we want to determine which of the two is growing and which is declining

From the rate of change of both, we can determine this. Looking at the differential equation for the first one, we can see that it is of positive value. Looking at the differential equation for the second one. we can see it is of negative value

While a positive change rate indicates growth, a negative change rate will indicate otherwise

Hence, we can conclude that the one with a negative rate change will indicate a declining population

8 0

3 years ago