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sattari [20]
3 years ago
6

Identify each process labeled in the diagram

Physics
1 answer:
marishachu [46]3 years ago
3 0
I am going to need a picture for this question
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The solar system is really big! To give you an idea of its dimensions, think that if the Sun was Washington DC and Mercury was t
12345 [234]

The sun is the center of the solar system which is surrounded by the nine planets and they tend to orbit the sun in concentric circles with the sun as the center.

<h3>What is the solar system?</h3>

The term solar system has to do with the arrangement of the sun and the planets. The sun lies at the focus of the solar system. Now we know that there are nine planets that orbit around the sun. The distance between the planets and the sun depends on their relative proximity to each other.

Thus, the sun is the center of the solar system which is surrounded by the nine planets and they tend to orbit the sun in concentric circles with the sun as the center.

Learn more about solar system:brainly.com/question/12075871

#SPJ1

8 0
1 year ago
The boiling point of water is 91.30 °C on the
Taya2010 [7]

Answer:

196.34 °F

Explanation:

To convert from degrees celsius to degrees fahrenheit, use this equation:

(°C * 9/5) + 32 = °F

So, using this equation:

(91.30 * 9/5) + 32 = °F

196.34 + 32 = °F

°F = 196.34

Hope this helps!

3 0
3 years ago
Clay Matthews, a linebacker for the Green Bay Packers, can reach a speed of 10.0 m/s. At the start of a play, Matthews runs down
MA_775_DIABLO [31]

Answer:

a)   D_ total = 18.54 m,   b)        v = 6.55 m / s

Explanation:

In this exercise we must find the displacement of the player.

a) Let's start with the initial displacement, d = 8 m at a 45º angle, use trigonometry to find the components

           sin 45 = y₁ / d

           cos 45 = x₁ / d

           y₁ = d sin 45

           x₁ = d sin 45

           y₁ = 8 sin 45 = 5,657 m

           x₁ = 8 cos 45 = 5,657 m

The second offset is d₂ = 12m at 90 of the 50 yard

            y₂ = 12 m

            x₂ = 0

total displacement

          y_total = y₁ + y₂

          y_total = 5,657 + 12

          y_total = 17,657 m

          x_total = x₁ + x₂

          x_total = 5,657 + 0

          x_total = 5,657 m

          D_total =   17.657 i^+ 5.657 j^  m

          D_total = Ra (17.657 2 + 5.657 2)

          D_ total = 18.54 m

b) the average speed is requested, which is the offset carried out in the time used

           v = Δx /Δt

the distance traveled using the pythagorean theorem is

         r = √ (d1² + d2²)

          r = √ (8² + 12²)

          r = 14.42 m

The time used for this shredding is

         t = t1 + t2

         t = 1 + 1.2

         t = 2.2 s

let's calculate the average speed

         v = 14.42 / 2.2

         v = 6.55 m / s

8 0
3 years ago
Your friend says that the force that the sun exerts on earth is much larger than the force that earth exerts on the sun. part a
Verizon [17]
I disagree with that opinion, and I have solid Physics to back me up.

The forces of gravity are always equal in both directions. The sun pulls the Earth with exactly the same force with which the Earth pulls the sun.

It may seem weird, but your weight on Earth is exactly the same as the Earth's weight on you. For the same reason.
8 0
3 years ago
Read 2 more answers
A projectile is launched from ground level to the top of a cliff which is 195 m away and 155 m high. If the projectile lands on
muminat

Answer:

66.02m/s

Explanation:

the equation describing the distance covered in the horizontal direction is

x=ucos\alpha t-(1/2)gt^{2} but the acceleration in the horizontal path is zero, hence we have

x=ucos\alpha t

Since the horizontal distance covered is 155m at 7.6secs, we have ucos\alpha =\frac{155}{7.6} \\ucos\alpha =20.38.............equation 1

Also from the vertical path, the distance covered is expressed as

y=usin\alpha t-(1/2)gt^{2}

since the horizontal distance covered in 7.6secs is 195m, then we have

y=usin\alpha t-(1/2)gt^{2}\\y=7.6usin\alpha -4.9(7.6)^{2}\\478.02=7.6usin\alpha \\usin\alpha =62.9...........equation 2

Hence if we divide both equation 1 and 2 we arrive at

\frac{usin\alpha }{ucos\alpha } =\frac{62.9}{20.38} \\tan\alpha =3.08\\\alpha =tan^{-1}(3.08)\\\alpha =72.02^{0}\\

Hence if we substitute the angle into the equation 1 we have

ucos72.02=20.38\\u=66.02m/s

Hence the initial velocity is 66.02m/s

3 0
3 years ago
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