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viktelen [127]
2 years ago
10

Question 6: Iron metal and chlorine gas react to form iron (III) chloride: 2 Fe(s) + 3 Cl2 (g) → 2 FeCl3 (s)

Chemistry
1 answer:
Bas_tet [7]2 years ago
4 0

10 gm of Fe will consumes 19 gm Cl₂ and will produces 29 gm FeCl₃.

What ois Theoretical yield ?

The quantity of a product obtained from a reaction is expressed in terms of the yield of the reaction.

The amount of product predicted by stoichiometry is called the theoretical yield, whereas the amount obtained actually is called the actual yield.

  • As 2 moles (111.68 g) of Fe consumes 213 gm of Cl₂ to produce 2FeCl₃

Therefore ,

10 gm of Fe will consumes = 213 / 111.68 x 10 = 19 gm Cl₂

  • As 2 moles (111.68 g) of Fe produces 2 mole (324 gm) of FeCl₃

Therefore ,

10 gm of Fe will produces = 324 / 111.68 x 10 = 29 gm FeCl₃

Hence , 10 gm of Fe will consumes 19 gm Cl₂ and will produces 29 gm FeCl₃.

Learn more about Theoretical yield here ;

brainly.com/question/12704041

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Find the wavelength of the electromagnetic radiation with a frequency of 3x10^-18Hz (Show Work)
aalyn [17]

Answer:

λ   = 1×10²⁶m

Explanation:

Given data:

Wavelength of radiation =  ?

Frequency of radiation = 3×10⁻¹⁸Hz

Solution:

Formula:

c = f × λ

c = speed of wave = 3×10⁸ m/s

by putting values,

3×10⁸ m/s =   3×10⁻¹⁸Hz  × λ

λ  =  3×10⁸ m/s /  3×10⁻¹⁸s⁻¹

λ   = 1×10²⁶m

5 0
3 years ago
Which of the following factors could you change in a system and not change its induced EMF?
krok68 [10]
The options attached to the question above are listed below:
A. Magnetic field.
B. Type of wire.
C. Velocity of the wire.
D. Length of the wire in the field.

ANSWER
The correct option is B.
The factors that determine the induced current in a system are: the number of wires in the coil, the strength of the magnetic field and speed of armature rotation [speed of cutting]. Generally, the induced electromotive force across a conductor is equal to the rate at which magnetic flux is cut by the conductor. The type of wire used does not affect the induced EMF.
8 0
3 years ago
Read 2 more answers
When equal moles of an acid and a base are mixed, after reaction the two are compounds are said to be at the _______________. Se
Elodia [21]

Answer:

when equal moles of an acid and base are mixed,after reaction the two are compounds are said to be at the Equivalent point.

3 0
3 years ago
You need to produce a buffer solution that has a pH of 5.50. You already have a solution that contains 10 mmol (millimoles) of a
balandron [24]

Answer:

56.9 mmoles of acetate are required in this buffer

Explanation:

To solve this, we can think in the Henderson Hasselbach equation:

pH = pKa + log ([CH₃COO⁻] / [CH₃COOH])

To make the buffer we know:

CH₃COOH  +  H₂O  ⇄   CH₃COO⁻  +  H₃O⁺     Ka

We know that Ka from acetic acid is: 1.8×10⁻⁵

pKa = - log Ka

pKa = 4.74

We replace data:

5.5 = 4.74 + log ([acetate] / 10 mmol)

5.5 - 4.74 = log ([acetate] / 10 mmol)

0.755 = log ([acetate] / 10 mmol)

10⁰'⁷⁵⁵ = ([acetate] / 10 mmol)

5.69 = ([acetate] / 10 mmol)

5.69 . 10 = [acetate] → 56.9 mmoles

6 0
3 years ago
From the value Kf=1.2×109 for Ni(NH3)62+, calculate the concentration of NH3 required to just dissolve 0.016 mol of NiC2O4 (Ksp
Nina [5.8K]

<u>Answer:</u> The concentration of NH_3 required will be 0.285 M.

<u>Explanation:</u>

To calculate the molarity of NiC_2O_4, we use the equation:

\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}

Moles of NiC_2O_4 = 0.016 moles

Volume of solution = 1 L

Putting values in above equation, we get:

\text{Molarity of }NiC_2O_4=\frac{0.016mol}{1L}=0.016M

For the given chemical equations:

NiC_2O_4(s)\rightleftharpoons Ni^{2+}(aq.)+C_2O_4^{2-}(aq.);K_{sp}=4.0\times 10^{-10}

Ni^{2+}(aq.)+6NH_3(aq.)\rightleftharpoons [Ni(NH_3)_6]^{2+}+C_2O_4^{2-}(aq.);K_f=1.2\times 10^9

Net equation: NiC_2O_4(s)+6NH_3(aq.)\rightleftharpoons [Ni(NH_3)_6]^{2+}+C_2O_4^{2-}(aq.);K=?

To calculate the equilibrium constant, K for above equation, we get:

K=K_{sp}\times K_f\\K=(4.0\times 10^{-10})\times (1.2\times 10^9)=0.48

The expression for equilibrium constant of above equation is:

K=\frac{[C_2O_4^{2-}][[Ni(NH_3)_6]^{2+}]}{[NiC_2O_4][NH_3]^6}

As, NiC_2O_4 is a solid, so its activity is taken as 1 and so for C_2O_4^{2-}

We are given:

[[Ni(NH_3)_6]^{2+}]=0.016M

Putting values in above equations, we get:

0.48=\frac{0.016}{[NH_3]^6}}

[NH_3]=0.285M

Hence, the concentration of NH_3 required will be 0.285 M.

7 0
3 years ago
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