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VMariaS [17]
2 years ago
11

Whose view that matter is infinitely divisible was considered correct for most of the last two millennia?.

Chemistry
1 answer:
sergejj [24]2 years ago
6 0

Aristotle and Democritus (to some extent) view that matter is infinitely divisible was considered correct for most of the last two millennia

<h3>What is Matter ?</h3>

Anything that occupies space and have some mass is known as matter.

Aristotle believed that everything was comprised of earth, air, water, and fire, which were infinitely divisible.

Democritus stated that matter was subdivided into indivisible and immutable particles that created the appearance of change when they joined and separated from others.

Learn more about Matter here ;

brainly.com/question/17268444

#SPJ1

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Answer:

<h2>It gets cooler.</h2>

Explanation:

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Marie is working on formulations of a new type of paint that will last longer and be more durable on metal surfaces in order to
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Answer:

The answer is: Applied Chemistry

Explanation:

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3 years ago
For the equilibrium
Mamont248 [21]

Answer:

Equilibrium concentrations of the gases are

H_2S=0.596M

H_2=0.004 M

S_2=0.002 M

Explanation:

We are given that  for the equilibrium

2H_2S\rightleftharpoons 2H_2(g)+S_2(g)

k_c=9.0\times 10^{-8}

Temperature, T=700^{\circ}C

Initial concentration of

H_2S=0.30M

H_2=0.30 M

S_2=0.150 M

We have to find the equilibrium concentration of gases.

After certain time

2x number of moles  of reactant reduced and form product

Concentration of

H_2S=0.30+2x

H_2=0.30-2x

S_2=0.150-x

At equilibrium

Equilibrium constant

K_c=\frac{product}{Reactant}=\frac{[H_2]^2[S_2]}{[H_2S]^2}

Substitute the values

9\times 10^{-8}=\frac{(0.30-2x)^2(0.150-x)}{(0.30+2x)^2}

9\times 10^{-8}=\frac{(0.30-2x)^2(0.150-x)}{(0.30+2x)^2}

9\times 10^{-8}=\frac{(0.30-2x)^2(0.150-x)}{(0.30+2x)^2}

By solving we get

x\approx 0.148

Now, equilibrium concentration  of gases

H_2S=0.30+2(0.148)=0.596M

H_2=0.30-2(0.148)=0.004 M

S_2=0.150-0.148=0.002 M

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