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3 years ago

Describe the rise and fall of a basketball using the concepts of kinetic energy and potential energy

1 answer:

Colt1911 [192]3 years ago

8 0

The equilibrium of the basketball makes it bounce lower every time. If it had perfect equilibrium, then it would bounce up to the same height every time. The kinetic energy is from when the ball hits the ground and is bouncing back up. But gravity will soon make it potential when it stays on the ground and when it stops rolling. When it rolls, the kinetic energy keeps it rolling until it gets so weak, there is only potential energy left to keep it stat

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One hazard of space travel is debris left by previous missions. There are several thousand objects orbiting Earth that are large

Citrus2011 [14]

Answer:

The correct answer is "6666.67 N".

Explanation:

The given values are:

Mass,

m = 0.100

Relative speed,

v = 4.00 x 10³

time,

t = 6.00 x 10⁻⁸

As we know,

⇒ $F=m(\frac{\Delta v}{\Delta t} )$

On substituting the given values, we get

⇒ $=0.100\times 10^{-6}(\frac{4\times 10^3}{6\times 10^{-8}} )$

⇒ $=6666.67 \ N$

7 0

3 years ago

A baton twirler is twirling her aluminum baton in a horizontal circle at a rate of 2.33 revolutions per second. A baton held hor

Nata [24]

Answer:

Explanation:

Given that;

horizontal circle at a rate of 2.33 revolutions per second

the magnetic field of the Earth is 0.500 gauss

the baton is 60.1 cm in length.

the magnetic field is oriented at 14.42°

we wil get the area due to rotation of radius of baton is

$\Delta A = \frac{1}{2} \Delta \theta R^2$

The formula for the induced emf is

$E = \frac{\Delta \phi}{\Delta t}$

$\phi = \texttt {magnetic flux}$

$E=\frac{\Delta (BA) }{\Delta t}$

$=B\frac{\Delta A}{\Delta t}$

B is the magnetic field strength

substitute

$\texttt {substitute}\ \frac{1}{2} \Delta \theta R^2 \ \ for \Delta A$

$E=B\frac{(\Delta \theta R^3/2)}{\Delta t} \\\\=\frac{1}{2} BR^2\omega$

The magnetic field of the earth is oriented at 14.42

$\omega =2.33\\\\L=60.1c,\\\\\theta=14.42\\\\B=0.5$

we plug in the values in the equation above

so, the induce EMF will be

$E=\frac{1}{2} \times (B\sin \theta)R^2\omega\\\\E=\frac{1}{2} \times (B\sin \theta)(\frac{L}{2} )\omega$

$=\frac{1}{2} \times0.5gauss\times\frac{0.0001T}{1gauss} \times\sin 14.42\times(\frac{60.1\times10^-^2m}{2} )^2(2.33rev/s)(\frac{2\pi rad}{1rev} )\\\\=2.5\times10^-^5\times0.2490\times0.0903\times14.63982\\\\=2.5\times10^-^5\times0.32917\\\\=8.229\times10^-^6V$

6 0

3 years ago

The speed of an object and the direction in which it moves constitute a vector quantity known as the velocity. an ostrich is run

Orlov [11]

Velocity of an object is its rate of change of the object's position per interval of time. Velocity is a vector quantity which means that it consists of a magnitude and a direction. Magnitude is represented by the speed and the direction is represented by the angle. To determine the velocity components, we use trigonometric functions to determine the angle of the components. For the north component we, use the sine function while, for the west component, we use the cosine function. We calculate as follows:
north velocity component = (16.8 m/s) (sin 54°) = 16.4 m/s
<span>west velocity component = (16.8 m/s) (cos 54°) = 3.49 m/s</span>

6 0

3 years ago

Which action might lead scientists to develop new explanations about the

VikaD [51]

Answer:

vrzjxuxuxjcckhcouvou

Explanation:

gghhjjokjjhghhrjxjxkyxygbjv

5 0

3 years ago

If the applied force (F) is 14 N and the frictional force (f) is 3 N, what would the acceleration be on this 3.5 kg box?

Helga [31]

Answer:a = F/m so

11/3.5 times= 3.14 m/s

Explanation:

4 0

2 years ago