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Answer:
V₂ = 1518L
Explanation:
-Using combined gas law:
<em>Where P is pressure, V is volume and T is absolute temperature of 1, initial state and 2, final state of the gas.</em>
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<em>Initial states:</em>
P₁ = 743 torr
V₁ = 975L
T₁ = 30°C + 273.15K = 303.15K
P₂ = 375 mmHg = torr
V₂ = Our incognite
T₂ = -35°C + 273.15K = 238.15K
Replacing:
Here we have to draw the major product in the acid catalysed hydration reaction of 4-ethyl-3,3-dimethyl-1-hexene.
The 4-ethyl-3,3-dimethyl-1-hexene converts to 2-hydroxy-4-ethyl-3,3-dimethyl-1-hexane as a major product by acid catalyzed hydration reaction.
The acid catalyzed hydration of an alkene is the Sn¹ reaction. Where in the first step a carbocation is generated. The stability of the carbocation depends upon the position of the neighboring group having +I inductive effect.
In the next step the water molecule attack the carbocation and the corresponding alcohol is produced.
In 4-ethyl-3,3-dimethyl-1-hexene the carbocation formed in the C₂ position which is more stable than the C₁ position due to presence of the dimethyl and ethyl group in the neighboring position which have strong +I inductive effect. This is absence in C₁ position.
In the next step the water molecule attack the C₂ position to form the alcohol.
4-ethyl-3,3-dimethyl-1-hexene converts to 2-hydroxy-4-ethyl-3,3-dimethyl-1-hexane by acid catalyzed hydration reaction which is the major product along with 1-hydroxy-4-ethyl-3,3-dimethyl-1-hexane as a minor product.
The reaction mechanism is shown in the image.
