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1 year ago

How do light waves differ from sound waves?

Physics

2 answers:

Pie1 year ago

6 0

Light waves are electromagnetic. And, sound waves are mechanical.
Hope this helps! :)

insens350 [35]1 year ago

5 0

Answer:

Light waves are electromagnetic waves while sound waves are mechanical waves. :)

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Which of these organisms are there the fewest of on Earth?

givi [52]

Need a graph or a picture

3 0

3 years ago

When discussing Newton's laws of motion,which terms do people most likely yse when talking about Newton's third law of motion?

mestny [16]

When discussing Newton's laws of motion, particularly Newton's third law of motion, the terms that almost everyone will use are "action" and "reaction".

You must not take this to mean that they understand what they're talking about.

4 0

3 years ago

A dolphin can swim at a constant speed of 12.5 m/s. How

myrzilka [38]

Answer:

$\boxed {\tt 3.6 \ seconds}$

Explanation:

Time can be found by dividing the distance by the speed.

$t=\frac{d}{s}$

The distance is 45 meters and the speed is 12.5 meters per second.

$d= 45 \ m \\s= 12.5 \ m/s$

$t=\frac{45 \ m}{12.5 \ m/s}$

Divide. Note that the meters, or "m" will cancel each other out.

$t=\frac{45 }{12.5 \ s}$

$t=3.6 \ s$

It will take the dolphin 3.6 seconds to swim a distance of 45 meters are 12.5 meters per second.

6 0

3 years ago

Read 2 more answers

5p - 14 = 8 p + 4 find p

Digiron [165]

Answer:

Explanation:

5p - 14 = 8p + 4

5p = 8p + 18 <-- Moving constants to one side; add the same number of +14 to both sides.

-3p = 18. <-- The same thing with the variable itself.

p = -6 <-- Divide both sides by negative 3.

6 0

3 years ago

An artillery shell is launched on a flat, horizontal field at an angle of α = 40.8° with respect to the horizontal and with an i

Lina20 [59]

Answer:

1317.4 m

Explanation:

We are given that

Angle= $\alpha=40.8^{\circ}$

Initial speed = $v_0=346m/s$

We have to find the horizontal distance covered by the shell after 5.03 s.

Horizontal component of initial speed= $v_{ox}=v_0cos\theta=346cos40.8=261.9m/s$

Vertical component of initial speed= $v_{oy}=346sin40.8=226.1m/s$

Time=t=5.03 s

Horizontal distance = $Horizontal\;velocity\times time$

Using the formula

Horizontal distance= $261.9\times 5.03$

Horizontal distance=1317.4 m

Hence, the horizontal distance covered by the shell=1317.4 m

8 0

2 years ago