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ohaa [14]
2 years ago
15

How do light waves differ from sound waves?

Physics
2 answers:
Pie2 years ago
6 0
Light waves are electromagnetic. And, sound waves are mechanical.
Hope this helps! :)
insens350 [35]2 years ago
5 0

Answer:

Light waves are electromagnetic waves while sound waves are mechanical waves. :)

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Which wave form oscillates both parallel and perpendicular to the direction of the wave motion? transverse waves, longitudinal w
Solnce55 [7]
Hope this answer helps:)

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3 years ago
Driving on asphalt roads entails very little rolling resistance, so most of the energy of the engine goes to overcoming air resi
trapecia [35]

Answer:

a)  F_p=882N

b)  P=4410W

c)  V_p'=24135 ,n=15.2\%

Explanation:

From the question we are told that:

Mass M=1500kg

Velocity v=4.9m/s

Coefficient of Rolling Friction \mu=0.06

a)

Generally the equation for The Propulsion Force is mathematically given by

 F_p=\mu*mg

 F_p=0.06*1500*9.81

 F_p=882N

b)

Therefore Power Required at

 V_p=5.0m/s

 P=F_p*V_p

 P=882*5

 P=4410W

c)

 V_p' =15mpg

 V_p'=15*\frac{1609}

 V_p'=24135

Generally the equation for Work-done is mathematically given by

 W=F_p*V_p'

 W=882*15*1609

 W=2.13*10^7

Therefore

Efficiency

 n=\frac{W}{E}*100\%

Since

Energy in one gallon of gas is

 E=1.4*10^8J

Therefore

 n=\frac{2.1*10^7}{1.4*10^8}*100\%

 n=15.2\%

7 0
3 years ago
NASA is giving serious consideration to the concept of solar sailing. A solar sailcraft uses a large, lowmass sail and the energ
Elan Coil [88]

Answer:

a) the reflective surface has twice the energy transfer

b) A = 1.3 10²⁷ km²

c) the energy emitted by the sun is distributed in a sphere that depends on the square of the distance, and the gravitational force depends on the square of the distance

Explanation:

a) The pressure exerted on the candle is related to the variation of the momentum

          P = \frac{1}{c} \ \frac{dp}{dt}

in a case of absorption (inelastic shock) all the energy is absorbed therefore the pressure is

          P = \frac{1}{c} \ \frac{dp}{dt}

in the case of reflection (elastic shock) an energy is absorbed by absorbing the light and then by action and reaction the same energy is absorbed in the reflected light

          P = 2  \frac{1}{c} \ \frac{dp}{dt}

In conclusion, the reflective surface has twice the energy transfer.

             

b) pressure is defined with force per unit area

           P = F / A

           F = P A

this force must be greater than the gravitational force of attraction of the sun

           Fg = G m Ms / r²

let's look for the case that the two forces are equal

           F = Fg

           P A_sail = G m Ms = r²

suppose a fully reflective sail

           2 \frac{S}{c}  \ A_{sail} = G \frac{m M_s}{r^2}

           

The pointing vector is the power delivered per unit area

           S = I = P / A

where A is the area of ​​the sphere where the is distributed by the sun

            A = 4π r²

we substitute

            \frac{2P}{c} \ \frac{A_{sail}}{4 \pi   r^2} = G \frac{m M_s}{r^2}

            \frac{1}{2 \pi \ c } A_{sail} = G m M_s

            A = G  m M_s 2π c

let's calculate

            A = 6.67 10⁻¹¹  10000 2 10³⁰ 2π  3 10⁸

            A = 1,257 10³³ m²

let's reduce to km²

            A = 1.3 10³³ m² (1km / 10³ m) ²

            A = 1.3 10²⁷ km²

c) The size of the candle is independent of the distance to the sun because the energy emitted by the sun is distributed in a sphere that depends on the square of the distance, and the gravitational force depends on the square of the distance, therefore the two dependencies are canceled.

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The answer to this is Ar ( Argon)
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The formulas into H2O and CO2 are present molecules which are defined as
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H2O is water
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