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ohaa [14]
2 years ago
15

How do light waves differ from sound waves?

Physics
2 answers:
Pie2 years ago
6 0
Light waves are electromagnetic. And, sound waves are mechanical.
Hope this helps! :)
insens350 [35]2 years ago
5 0

Answer:

Light waves are electromagnetic waves while sound waves are mechanical waves. :)

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Convection is heat transfer through the movement of liquids and gases.

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Help m-e-e people -_-!​
xxTIMURxx [149]

Answer:

the answer is

Explanation:For equilibrium

Weight = Tension

mg=T

∴T=4×3.1π=12.4πN (as can be inferred from the question)

Y=

△l/l

T/A

​

=

1000

0.031

​

/20

12.4π/π(

1000

2

​

)

2

​

=

4×0.031

12.4×20×1000×(1000)

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​

=2×10

12

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6 0
2 years ago
This question is about sound waves and light waves.
kenny6666 [7]

Answer:

you had it right

Explanation:

4 0
3 years ago
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I need to know this right away please help
Ahat [919]
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8 0
3 years ago
Will mark the brainliest
AysviL [449]

Answer:

The impulse transferred to the nail is 0.01 kg*m/s.

Explanation:

The impulse (J) transferred to the nail can be found using the following equation:

J = \Delta p = p_{f} - p_{i}

Where:                                                                

p_{f}: is the final momentum

p_{i}: is the initial momentum

The initial momentum is given by:

p_{i} = m_{1}v_{1_{i}} + m_{2}v_{2_{i}}

Where 1 is for the hammer and 2 is for the nail.

Since the hammer is moving down (in the negative direction):

v_{1_{i}} = -10 m/s

And because the nail is not moving:

v_{2_{i}}= 0                      

p_{i} = m_{1}v_{1_{i}} = 0.25 kg*(-10 m/s) = -2.5 kg*m/s

Now, the final momentum can be found taking into account that the hammer remains in contact with the nail during and after the blow:

p_{f} = m_{1}v_{1_{f}} + m_{2}v_{2_{f}}

Since the hammer and the nail are moving in the negative direction:

v_{1_{f}} = v_{2_{f}} = -9.7 m/s

p_{f} = -9.7 m/s(7 \cdot 10^{-3} kg + 0.25 kg) = -2.49 kg*m/s

Finally, the impulse is:

J = p_{f} - p_{i} = - 2.49 kg*m/s + 2.50 kg*m/s = 0.01 kg*m/s

Therefore, the impulse transferred to the nail is 0.01 kg*m/s.

I hope it helps you!                                                                                                                                                                                                                                                                                                                                                                                                                    

7 0
3 years ago
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