The answer is 24 J
F K =.25*8 N
= 2N
F = f k = 2 N
Since a = 0
W = f * s
2 N * 12 m = 24 J
The coefficient of friction is a ratio used to quantify the friction force among two gadgets when it comes to the everyday pressure this is keeping them collectively. The coefficient of friction is critical attention at some stage in material selection and floor requirement determination.
For instance, ice on steel has a low coefficient of friction – the 2 materials slide past each different without problems – whilst rubber on the pavement has an excessive coefficient of friction – the substances no longer slide past each other without difficulty.
The coefficient of friction is dimensionless and it does not have any unit. it is a scalar, meaning the direction of the force does not have an effect on the physical quantity. The coefficient of friction depends on the gadgets that are causing friction.
Learn more about the coefficient of friction here brainly.com/question/20241845
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C
The potential energy is mgh, she knows the mass, she needs the acceleration due to gravity and the height of the ball
Penn Foster Students: Light can pass through Object B faster than it can pass through Object A
Answer:
9.67 A
Explanation:
The weight of a student with a mass of m = 75 kg is:
![W=mg=(75 kg)(9.8 m/s^2)=735 N](https://tex.z-dn.net/?f=W%3Dmg%3D%2875%20kg%29%289.8%20m%2Fs%5E2%29%3D735%20N)
where g=9.8 m/s^2 is the acceleration due to gravity.
We want the magnetic force on the wire to be equal to this weight. The magnetic force on the wire is
![F=ILB sin \theta](https://tex.z-dn.net/?f=F%3DILB%20sin%20%5Ctheta)
where
I is the current in the wire
L = 2.0 m is the length of the wire
B = 38 T is the magnetic field
is the angle between the direction of B and L
Since we want W=F, we can write
![ILB sin \theta=W](https://tex.z-dn.net/?f=ILB%20sin%20%5Ctheta%3DW)
And we can solve it to find the current I:
![I=\frac{W}{BLsin\theta}=\frac{735 N}{(38 T)(2.0 m)(sin 90^{\circ})}=9.67 A](https://tex.z-dn.net/?f=I%3D%5Cfrac%7BW%7D%7BBLsin%5Ctheta%7D%3D%5Cfrac%7B735%20N%7D%7B%2838%20T%29%282.0%20m%29%28sin%2090%5E%7B%5Ccirc%7D%29%7D%3D9.67%20A)