I don't know how 5°C cooled to 85°C but the answer would be 12.878L
Answer:
the concentration of bicarbonate is <em>[HCO₃⁻] = 0,03996 M </em>and carbonate is <em>[CO₃²⁻] = 3,56x10⁻⁵ M.</em>
Explanation:
Carbonate-bicarbonate is:
HCO₃⁻ ⇄ CO₃²⁻ + H⁺ With pka = 10,25
Using Henderson-Hasselbalach formula:
pH = pka + log₁₀![\frac{[CO_{3}^{2-}]}{[HCO_{3}^-]}](https://tex.z-dn.net/?f=%5Cfrac%7B%5BCO_%7B3%7D%5E%7B2-%7D%5D%7D%7B%5BHCO_%7B3%7D%5E-%5D%7D)
7,2 = 10,25 + log₁₀
8,91x10⁻⁴ = <em>(1)</em>
Also:
0,040 M = [CO₃²⁻] + [HCO₃⁻] <em>(2)</em>
Replacing (2) in 1:
<em>[HCO₃⁻] = 0,03996 M</em>
Thus:
<em>[CO₃²⁻] = 3,56x10⁻⁵ M</em>
I hope it helps.
A mixture is easy to separate out into its parts because each part of the mixture keeps is molecular properties
Answer:
280 mL
Explanation:
Given data:
Mass of CuSO₄ = 55.75 g
Molarity of CuSO₄ = 1.25 M
Volume of CuSO₄ = ?
Solution:
First of all we will calculate the number of moles.
Number of moles:
Number of moles = mass / molar mass
Number of moles = 55.75 g/ 159.6 g/mol
Number of moles = 0.35 mol
Volume of CuSO₄:
Molarity = number of moles / volume in litter
1.25 M = 0.35 mol / volume in litter
Volume in litter = 0.35 mol / 1.25 M
Volume in litter = 0.28 L
Volume in milliliter:
0.28 L × 1000 mL/ 1 L = 280 mL
The answer is (1) the reaction is exothermic because it releases heat. From the reaction, we can see that the heat is at the right of the equation which means the reaction releases heat. So it is called exothermic reaction. Endothermic reaction absorbs heat.
