Answer:
Option B.
Explanation:
As any reaction of combustion, the O₂ is a reactant and the products are CO₂ and H₂O. Combustion reaction for ethane is:
2C₂H₆ + 7O₂ → 4CO₂ + 6H₂O
So 2 moles of ethane react with 7 moles of oxygen to make 4 moles of dioxide and 6 moles of water.
Then 2 moles of ethane will produce 4 moles of CO₂
C2H2O4 C2HO4- + H+
0.175 - x x x + y
C2HO4- c2o42– + H+
x - y y x + y
K2 = (y) (x +y) / (x-y)
As, y << x
So, K2 = (y) (x) / (x)
K2 = y =6.1 × 10^–5
Hence, concentration of (c2o42–) 6.1 × 10^–5 M
Answer:
Explanation: Polar molecules interact with each other by forces such as dipole-dipole interactions whereas nonpolar molecules interact with each other through London dispersion forces
