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Gnom [1K]
2 years ago
5

Laser light of wavelength 500.0 nm illuminates two identi- cal slits, producing an interference pattern on a screen 90.0 cm from

the slits. the bright bands are 1.00 cm apart, and the third bright bands on either side of the central maximum are missing in the pattern. find the width and the separation of the two slits.
Physics
1 answer:
sergeinik [125]2 years ago
5 0

The width and the separation of the two slits are 15μm and 45μm.

<h3>What is wavelength?</h3>

The wavelength is the distance between the adjacent crest or trough of the sinusoidal wave.

Given is the laser light of wavelength λ= 500.0 nm = 500x 10⁻⁹ m illuminates two identical slits, producing an interference pattern on a screen D =90.0 cm from the slits. the bright bands distance Δy = 1.00 cm apart, and the third bright bands on either side of the central maximum are missing in the pattern.

If d = separation between the two slits  and a is the width of the slit

dsinθ/asinθ =m(max) λ/ m(min)λ

d/a = m(max) / m(min)..................(1)

where  m(max)= ±3.0 and  m(min)=1.0

So, d.a = 3

The distance from the central maxima to the third minimum fringe

y₃ = 3Δy

and the angle formed is

tan θ₃ = y₃/D or  3Δy/D

Put the values, we get

θ₃ =1.91°

From the equation, a sinθ = m(min)λ

a = 1 x 500 x 10⁻⁹/sin 1.91

a = 15 x 10⁻⁶ m or 15μm

From the equation, dsinθ= m(max) λ

d = 3 x 500 x 10⁻⁹/sin 1.91

d = 45 x 10⁻⁶ m or 45μm

Thus, the separation and the width are 45μm and  15μm

Learn more about wavelength.

brainly.com/question/13533093

#SPJ1

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