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Leokris [45]
2 years ago
13

A 0.420 M Ca(OH)2 solution was prepared by dissolving 64.0 grams of Ca(OH)2 in enough water. What is the total volume of the sol

ution formed? (4 points)
Select one:
a.1.07 liters
b.1.23 liters
c.2.05 liters
d.2.18 liters Incorrect
Chemistry
1 answer:
nikitadnepr [17]2 years ago
6 0

The volume of the solution is given below which can be calculated using the molarity formula as 2.18 litres.

<h3>Define the molarity of a solution.</h3>

Molarity (M) is the amount of a substance in a certain volume of solution. Molarity is defined as the moles of a solute per litres of a solution.

Molality = \frac{Moles \;solute}{Volume \;of \;solution \;in \;litre}

Given data:

M= 0.420M

mass = 64.0 grams

Molar Mass= 74g/mol

To find:

The volume of solution=?

The calculation for a number of moles:

n= \frac{m}{M}

n= \frac{64}{70}

n= 0.91 moles

Molarity=  \frac{n}{V}

V= \frac{0.91}{0.420}

V= 2.1768 litres

Thus, the volume of the solution is 2.18 litres.

Find more information about Molarity here:

brainly.com/question/26873446

#SPJ1

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<h3>Answer:</h3>

60 g O₂

<h3>General Formulas and Concepts: </h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

<u>Chemistry</u>

<u>Atomic Structure</u>

  • Reading a Periodic Table

<u>Stoichiometry</u>

  • Using Dimensional Analysis
<h3>Explanation: </h3>

<u>Step 1: Define</u>

[RxN - Balanced]   CH₄ + 2O₂ → CO₂ + 2H₂O

[Given]   2 mol H₂O

[Solve]   x g O₂

<u>Step 2: Identify Conversions</u>

[RxN] 2 mol H₂O → 2 mol O₂

[PT] Molar Mass of O - 16.00 g/mol

Molar Mass of O₂ - 2(16.00) = 32.00 g/mol

<u>Step 3: Stoichiometry</u>

  1. Set up conversion:                    \displaystyle 2 \ mol \ H_2O(\frac{2 \ mol \ O_2}{2 \ mol \ H_2O})(\frac{32.00 \ g \ O_2}{1 \ mol \ O_2})
  2. Divide/Multiply:                          \displaystyle 64.00 \ g \ O_2

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 1 sig fig.</em>

64.00 g O₂ ≈ 60 g O₂

8 0
3 years ago
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Which of the following describes the products of a chemical reaction?
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Answer:

B. The substances that are formed

Explanation:

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can i have brainliest? and btw, let me know if you get it right! hope i helped <3

5 0
3 years ago
In the equilibrium constant expression for the reaction below what is the correct exponent for N2O4?
irga5000 [103]
As we have the balanced reaction equation is:

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from this balanced equation, we can get the equilibrium constant expression

KC = [NO2]^2[N2O4]^1

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is 2NO2 in the balanced equation.

and [N2O4] is with 1 exponent of the stoichiometric and we can see that from the balanced equation as N2O4 is 1 N2O4 in the balanced equation. 

∴ the correct exponent for N2O4 in the equilibrium constant expression is 1 
7 0
4 years ago
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