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Leokris [45]
2 years ago
13

A 0.420 M Ca(OH)2 solution was prepared by dissolving 64.0 grams of Ca(OH)2 in enough water. What is the total volume of the sol

ution formed? (4 points)
Select one:
a.1.07 liters
b.1.23 liters
c.2.05 liters
d.2.18 liters Incorrect
Chemistry
1 answer:
nikitadnepr [17]2 years ago
6 0

The volume of the solution is given below which can be calculated using the molarity formula as 2.18 litres.

<h3>Define the molarity of a solution.</h3>

Molarity (M) is the amount of a substance in a certain volume of solution. Molarity is defined as the moles of a solute per litres of a solution.

Molality = \frac{Moles \;solute}{Volume \;of \;solution \;in \;litre}

Given data:

M= 0.420M

mass = 64.0 grams

Molar Mass= 74g/mol

To find:

The volume of solution=?

The calculation for a number of moles:

n= \frac{m}{M}

n= \frac{64}{70}

n= 0.91 moles

Molarity=  \frac{n}{V}

V= \frac{0.91}{0.420}

V= 2.1768 litres

Thus, the volume of the solution is 2.18 litres.

Find more information about Molarity here:

brainly.com/question/26873446

#SPJ1

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LUCKY_DIMON [66]

Answer:

The most reasonable estimate for the O–S–O bond angle in hyposulfite = 106°

Explanation:

Hyposulphite (so₂²⁻) is polyatomic ion .

According to VSEPR model

Total elrctron pairs  =\frac{1}{2} [V+X -C+A]

V = Valence shell electrons of central element

X = No. of monovalent surrounding atoms

C = Cationic charge

A = Anionic charge

Total electron pairs =\frac{1}{2}[6+0-0+2]= 4

That is two bond pairs and two lone pairs

6 0
3 years ago
g Tibet (altitude above sea level is 29,028 ft) has an atmospheric pressure of 240. mm Hg. Calculate the boiling point of water
Marina CMI [18]

<u>Answer:</u> The boiling point of water in Tibet is 69.9°C

<u>Explanation:</u>

To calculate the boiling point of water in Tibet, we use the Clausius-Clayperon equation, which is:

\ln(\frac{P_2}{P_1})=\frac{\Delta H}{R}[\frac{1}{T_1}-\frac{1}{T_2}]

where,

P_1 = initial pressure which is the pressure at normal boiling point = 1 atm = 760 mmHg      (Conversion factor:  1 atm = 760 mmHg)

P_2 = final pressure = 240. mmHg

\Delta H_{vap} = Heat of vaporization = 40.7 kJ/mol = 40700 J/mol     (Conversion factor: 1 kJ = 1000 J)

R = Gas constant = 8.314 J/mol K

T_1 = initial temperature or normal boiling point of water = 100^oC=[100+273]K=373K

T_2 = final temperature = ?

Putting values in above equation, we get:

\ln(\frac{240}{760})=\frac{40700J/mol}{8.314J/mol.K}[\frac{1}{373}-\frac{1}{T_2}]\\\\-1.153=4895.36[\frac{T_2-373}{373T_2}]\\\\T_2=342.9K

Converting the temperature from kelvins to degree Celsius, by using the conversion factor:

T(K)=T(^oC)+273

342.9=T(^oC)+273\\T(^oC)=(342.9-273)=69.9^oC

Hence, the boiling point of water in Tibet is 69.9°C

3 0
3 years ago
What is the main idea of the article, "Great Wall of China"?
grin007 [14]

well, without the article, I'm guessing the main idea is about the Great Wall of China

7 0
3 years ago
An electron in an atom is known to be in a state with magnetic quantum number ml=0. What is the smallest possible value of the p
rusak2 [61]

Answer:

1

Explanation:

The principal quantum number, n, showsthe principal electron shell. which can inturn be describe as the most probable distance of the electrons from the nucleus, the larger the number n is, the farther the electron is from the nucleus, the larger the size of the orbital, and the larger the atom is. n can be any positive integer starting at 1, as n=1 designates the first principal shell (the innermost shell). When an electron is in an excited state or it gains energy, it may jump to the second principle shell, where n=2

As the energy of the electron increases, so does the principal quantum number, e.g., n = 3 indicates the third principal shell, n = 4 indicates the fourth principal shell, and so on. n=1,2,3,4…

On the other hand, the magnetic quantum number ml determines the number of orbitals and their orientation within a subshell. Consequently, its value depends on the orbital angular momentum quantum number l. Given a certain l, ml is an interval ranging from –l to +l, so it can be zero, a negative integer, or a positive integer. ml=−l,(−l+1),(−l+2),…,−2,−1,0,1,2,…(l–1),(l–2),+l

note also that: The orbital angular momentum quantum number l determines the shape of an orbital, and therefore the angular distribution. The number of angular nodes is equal to the value of the angular momentum quantum number l. Each value of l indicates a specific s, p, d, f subshell (each unique in shape.) The value of l is dependent on the principal quantum number n. Unlike n, the value of l can be zero. It can also be a positive integer, but it cannot be larger than one less than the principal quantum number (n-1): l=0,1,2,3,4…,(n−1).

So the answer is 1

3 0
3 years ago
Convert 66.8g to mg ! Thank you
igor_vitrenko [27]
66.8g to mg is 66800 hope this helps

8 0
3 years ago
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