A because when gravity and the force are equilibrium it tend to be equal or stay at rest or constant velocity. But when the force of a plane is less than the force of gravity it will go down to the ground. Unless when the force of a plane is greater than the force of gravity, the plane will move upward at increasing rate.
Hope this helps
The new acceleration is ![108 m/s^2](https://tex.z-dn.net/?f=108%20m%2Fs%5E2)
Explanation:
We can answer this problem by applying Newton's second law, which states that:
![F=ma](https://tex.z-dn.net/?f=F%3Dma)
where
F is the net force on an object
m is the mass of the object
a is its acceleration
The equation can be rewritten as
![a=\frac{F}{m}](https://tex.z-dn.net/?f=a%3D%5Cfrac%7BF%7D%7Bm%7D)
In this problem, the initial acceleration is
![a=18.0 m/s^2](https://tex.z-dn.net/?f=a%3D18.0%20m%2Fs%5E2)
Later:
- The net force is tripled: ![F'=3F](https://tex.z-dn.net/?f=F%27%3D3F)
- The mass is halved: ![m'=\frac{m}{2}](https://tex.z-dn.net/?f=m%27%3D%5Cfrac%7Bm%7D%7B2%7D)
Therefore, the new acceleration is:
![a'=\frac{F'}{m'}=\frac{3F}{m/2}=6\frac{F}{m}=6a](https://tex.z-dn.net/?f=a%27%3D%5Cfrac%7BF%27%7D%7Bm%27%7D%3D%5Cfrac%7B3F%7D%7Bm%2F2%7D%3D6%5Cfrac%7BF%7D%7Bm%7D%3D6a)
which means that the new acceleration is 6 times the original acceleration, therefore
![a'=6(18)=108 m/s^2](https://tex.z-dn.net/?f=a%27%3D6%2818%29%3D108%20m%2Fs%5E2)
Learn more about acceleration:
brainly.com/question/9527152
brainly.com/question/11181826
brainly.com/question/2506873
brainly.com/question/2562700
#LearnwithBrainly
Answer:
= 8.46 × 10³N
Explanation:
W = 1.3 × 10⁴
v₁ = 0
v (friction) = 95km/h = 26.4 m/s
t = 5s
f = 1450N
mass of body = W / g
=1.3 × 10⁴ / 9.8
=1327 kg
v(friction) = v + at
substitute in eqn 1
26.4 = 5a
a = 5.28 m/s
Force Net = F₁ + F₂ + F₃ = ma
F (engine) = ma + F
= 1327 (5.28) + 1450
= 8.46 × 10³N
The independent variable is how long the egg takes to cook
Answer:
Answered
Explanation:
a) What is the work done on the oven by the force F?
W = F * x
W = 120 N * (14.0 cos(37))
<<<< (x component)
W = 1341.71
b) ![F_f=\mu_k N](https://tex.z-dn.net/?f=F_f%3D%5Cmu_k%20N)
![F_f=0.25\times12\times9.8](https://tex.z-dn.net/?f=F_f%3D0.25%5Ctimes12%5Ctimes9.8)
= 29.4 N
![W_f= F_f\times x](https://tex.z-dn.net/?f=W_f%3D%20F_f%5Ctimes%20x)
![W_f= 29.0\times 14 cos(37)](https://tex.z-dn.net/?f=W_f%3D%2029.0%5Ctimes%2014%20cos%2837%29)
W_f= 328.72 J = 329 J
c) increase in the internal energy
U_2 = mgh
= 12*9.81*14sin(37)
= 991 J
d) the increase in oven's kinetic energy
U_1 + K_1 + W_other = U_2 + K_2
0 + 0 + (W_F - W_f ) = U_2 + K_2
1341.71 J - 329 J - 991 J = K_2
K_2 = 21.71 J
e) F - F_f = ma
(120N - 29.4N ) / 12.0kg = a
a = 7.55m/s^2
vf^2 = v0^2 + 2ax
vf^2 = 2(7.55m/s)(14.0m)
V_f = 14.5396m/s
K = 1/2(mv^2)
K = 1/2(12.0kg)(14.5396m/s)
K = 87.238J