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2 years ago

Tabitha knows the redshift value of a particular celestial object. What can she use this information most directly to find out?

Physics

1 answer:

AlekseyPX2 years ago

3 0

She can use the information of redshift of a celestial body is to find the age and distance of the object.

<h3>What is red shift?</h3>

'Red shift' is a critical idea for astronomers. The frequency of the light is increased, so the light is observed as moving towards the red side of the range.

Tabitha knows the redshift value of a particular celestial object. She uses this information to observe the consequence of the redshift.

Thus, the red shift value is used to determine the age and distance of the object.

Learn more about red shift.

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The planet Krypton has a mass of 7.6 × 1023 kg and radius of 1.7 × 106 m. What is the acceleration of an object in free fall nea

olga55 [171]

Answer:

17.55 m/s²

Explanation:

Parameters given:

Mass of Krypton, M = 7.6 * 10^23 kg

Radius, R = 1.7 * 10^6 m

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Acceleration due to gravity of planet of mass M is given as:

g = GM/R²

Since the object is close to the surface of Krypton, we can say that the distance from the Centre of Krypton is the radius of the planet Krypton.

Therefore,

g = (6.6726 * 10^(-11) * 7.6 * 10^23)/(1.7 * 10^6)²

g = 17.55 m/s²

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3 years ago

Mindy places a strip of zinc in a copper sulfate solution, as shown in the

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Answer:

C. The concentration of the copper sulfate is too low

Explanation:

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3 years ago

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Type the correct answer in the box. Round your answer to the nearest whole number. Calculate the man’s mass. (Use PE = m × g × h

Blababa [14]

Answer:

56 kg

Explanation:

The change in potential energy of the man is given by:

$\Delta U = mg \Delta h$

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$\Delta h$ is the change in height of the man

In this problem, we have:

$\Delta U=4620 J$ is the gain in potential energy

g = 9.8 m/s^2 is the gravitational acceleration

$\Delta h=8.4 m$ is the change in height

Re-arranging the equation and substituting the numbers, we find the mass:

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3 years ago

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Answer:

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Explanation:

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3 years ago

А A pool of water of refractive index

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Answer:

Apparent depth = 45 cm

Explanation:

The refractive index of water in a pool, n = 4/3

Real depth, d = 60 cm

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$n=\dfrac{d}{d'}\\\\d'=\dfrac{d}{n}\\\\d'=\dfrac{60}{\dfrac{4}{3}}\\\\d'=45\ cm$

So, the apparent depth is 45 cm.

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2 years ago