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2 years ago

A machine runs for 50 seconds with a steady power output of 100 watts. How many joules of work does the

Physics

1 answer:

liberstina [14]2 years ago

6 0

Answer:

The answer to your question is when time = 50 s, work = 5000 J

when time = 90 s, work = 9000 J

Explanation:

Data

time = 50 s or 90 s

Power = 100 watts

Power is defined as the rate of work done per unit of time.

Power = Work / time

-Solve for Work

Work = Power x time

-Substitution

Work = 100 x 50

-Result

Work = 5000

2.-When time = 90 s

Work = 100 x 90

-Result

Work = 9000 watts

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Answer: Hi!

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3 years ago

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When two hydrogen nuclei combine to form one helium nucleus, nuclear fusion has taken place. Please select the best answer from

kirill115 [55]

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3 years ago

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A ball has a mass of 1.5kg and is thrown straight up with a speed of 60m/s, what is the ball’s momentum:

madam [21]

Answer:

Assumption: the air resistance on this ball is negligible. Take $g = 10\; \rm m \cdot s^{-2}$ .

a. The momentum of the ball would be approximately $60\;\rm kg \cdot m \cdot s^{-1}$ two seconds after it is tossed into the air.

b. The momentum of the ball would be approximately $\rm \left(-45\; \rm kg \cdot m \cdot s^{-1}\right)$ three seconds after it reaches the highest point (assuming that it didn't hit the ground.) This momentum is smaller than zero because it points downwards.

Explanation:

The momentum $p$ of an object is equal its mass $m$ times its velocity $v$ . That is: $\vec{p} = m \cdot \vec{v}$ .

Assume that the air resistance on this ball is negligible. If that's the case, then the ball would accelerate downwards towards the ground at a constant $g \approx -10\; \rm m \cdot s^{-2}$ . In other words, its velocity would become approximately $10\; \rm m \cdot s^{-1}$ more negative every second.

The initial velocity of the ball is $60\; \rm m \cdot s^{-1}$ . After two seconds, its velocity would have become $60\;\rm m \cdot s^{-1} + 2\; \rm s \times \left(-10\;\rm m \cdot s^{-1}\right) = 40\; \rm m \cdot s^{-1}$ . The momentum of the ball at that time would be around $p = m \cdot v \approx 60\; \rm kg \cdot m \cdot s^{-1}$ .

When the ball is at the highest point of its trajectory, the velocity of the ball would be zero. However, the ball would continue to accelerate downwards towards the ground at a constant $g \approx -10\; \rm m \cdot s^{-2}$ . That's how the ball's velocity becomes negative.

After three more seconds, the velocity of the ball would be $0\; \rm m \cdot s^{-1} + 3\; \rm s \times \left(-10\; \rm m \cdot s^{-2}\right) = -30 \; \rm m \cdot s^{-1}$ . Accordingly, the ball's momentum at that moment would be $p = m \cdot v \approx \left(-45\; \rm kg \cdot m \cdot s^{-1}\right)$ .

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3 years ago

A certain lightbulb has a tungsten filament with a resistance of 26 Ω when cold and 170 Ω when hot. If the equation R = R0 [1 +

iris [78.8K]

Answer:

Explanation: The equation that relates resistance of tungsten at different temperatures is as follows

R = R₀ [1 + α ∆T] , R₀ is resistance at lower temperature , R is resistance at higher temperature . α is temperature coefficient of resistivity and ∆T is rise in temperature .

Putting the values

170 = 26 [1 + .0045 ∆T]

∆T = 1230.75

lower temperature = 40◦C

higher temperature = 1230 + 40

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3 years ago

If two protons and two neutrons are removed from the nucleus of an oxygen atom, a nucleus of which element remains?

trapecia [35]

Answer:

Carbon 12

Explanation:

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When you remove the nucleus from an oxygen atom, almost everything of the base oxygen is essentially stripped away. Since almost everything is made of carbon, and Carbon 12 is one of the most common forms of Carbon, Carbon 12 would be what is left.

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3 years ago