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mash [69]
2 years ago
15

My predicted height was lower than the final height i measured. this is because friction slowed the puck as it was sliding along

the track. do you agree or disagree with khadija
Physics
1 answer:
LekaFEV [45]2 years ago
6 0

I disagree since friction will cause the ultimate height to be lower than what was anticipated. To reduce the height, resist the action.

<h3> What is the height?</h3>

The vertical distance between an object's top and the bottom is defined as its height.

It is measured in centimeters, inches, meters, and other units. The height of the cliff is obtained by the Newton equation of motion.

My actual height was less than what I had anticipated. this is because the puck's movement along the track was impeded by friction.

To the Khalida, I object. Disagree, since friction will cause the ultimate height to be lower than the anticipated height. To reduce the height, resist the action.

Hence, I disagree with Khalida.

To learn more about the height, refer to the link;

brainly.com/question/10726356

#SPJ1

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Choose all the answers that apply. Power is calculated using ___.
antiseptic1488 [7]

Time , Work, Horsepower

Explanation:

In General, Power is defined as rate of doing work in physics.

1.) By work and Time, we can calculate power as follows,

                 Power = Work done per unit Time

                              = Work done / time

2.) From Horsepower we can directly get the power.

Horsepower (hp) is a unit to measure the  power, or the rate at which work is done, usually in  the output of engines or motors. There are many  types of horsepower. Two common ways of defining horsepower is being used today are the mechanical horsepower (or imperial horsepower), which is about 745.7 watts, and the metric horsepower, which is approximately 735.5 watts.

5 0
3 years ago
A parallel combination of a 1.13-μF capacitor and a 2.85-μF one is connected in series to a 4.25-μF capacitor. This three-capaci
Nata [24]

Answer:

(a) Charge of 4.25 μF capacitor is 35.46 μC.

(b) Charge of 1.13 μF capacitor is 10.05 μC.

(c) Charge of 2.85 μF capacitor is 25.36 μC.

Explanation:

Let C₁ , C₂ and C₃ are the capacitor which are connected to the battery having voltage V. According to the problem, C₁ and C₂ are connected in parallel. There equivalent capacitance is:

C₄ = C₁ + C₂

Substitute 1.13 μF for C₁ and 2.85 μF for C₂ in the above equation.

C₄ = ( 1.13 + 2.85 ) μF = 3.98 μF

Since, C₄ and C₃ are connected in series, there equivalent capacitance is:

C₅ = \frac{C_{3}C_{4}  }{C_{3} + C_{4}  }

Substitute 4.25 μF for C₃ and 3.98 μF for C₄ in the above equation.

C₅ = \frac{4.25\times3.98 }{4.25 + 3.98  }

C₅ = 2.05 μF

The charge on the equivalent capacitance is determine by the relation :

Q = C₅ V

Substitute 2.05 μF for C₅ and 17.3 volts for V in the above equation.

Q = 2.05 μF x 17.3  = 35.46 μC

Since, the capacitors C₃ and C₄ are connected in series, so the charge on these capacitors are equal to the charge on the equivalent capacitor C₅.

Charge on the capacitor, C₃ = 35.46 μC

Charge on the capacitor, C₄ = 35.46 μC

Voltage on the capacitor C₄ = \frac{Q}{C_{4} } = \frac{35.46\times10^{-6} }{3.98\times10^{-6}} = 8.90 volts

Since, C₁ and C₂ are connected in parallel, the voltage drop on both the capacitors are same, that is equal to 8.90 volts.

Charge on the capacitor, C₁ = C₁ V = 1.13 μF x 8.90 = 10.05 μC

Charge on the capacitor, C₂ = C₂ V = 2.85 μF x 8.90 = 25.36 μC

5 0
3 years ago
1 nanometer is equals to?
netineya [11]

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4 years ago
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Answer:

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