All categories

1 year ago

The average atomic mass of carbon is 12.01 amu. Based on the atomic

Chemistry

1 answer:

zvonat [6]1 year ago

7 0

Answer: There is a very large percentage of C-12.

Explanation:

The atomic mass is must closer to that of C-12 than of C-13, meaning that there is a much larger percentage of C-12.

You might be interested in

4.What volume of hydrogen gas at STP is produced when 2.5 grams of zinc react with an

ValentinkaMS [17]

Answer:

0.86

Explanation:

1mol of Zn has mass of 65.39g.The amount of Zn is 2.5g65.39g/mol=0.038mol.

The amount of H2 produced is the same as the amount of Zn consumed (0.038mol).

1mol of ideal gas will occupy 22.4L at STP.

The H2 will occupy 0.038mol×22.4L/mol=0.86L

5 0

2 years ago

A 7.45 L container holds a mixture of two gases at 15 °C. The partial pressures of gas A and gas B, respectively, are 0.364 atm

kogti [31]

Answer:

stored and active

Explanation:

both cannot be thransformed into another type of energy

8 0

2 years ago

A balloon at 32 °C is filled with 21 L of air. What would its volume be at a temperature of 52 °C, assuming pressure remains con

I am Lyosha [343]

Answer:C). 24L

Explanation: it works

4 0

3 years ago

Describe the importance of the nervous system:

elena-14-01-66 [18.8K]

Answer:

So you can feel the things outside of your body

Explanation:

3 0

2 years ago

Read 2 more answers

A gas that exerts a pressure of 537 torr in a container with a volume of 5.30 L will exert a pressure of 255 torr when transferr

ArbitrLikvidat [17]

Answer:- The gas needs to be transferred to a container with a volume of 11.2 L.

Solution:- From Boyle's law. "At constant temperature, Volume is inversely proportional to the pressure."

It means, the volume is decreased if the pressure is increased and vice versa.

Here, the Pressure is decreasing from 537 torr to 255 torr. So, the volume must increase and calculated by using the equation:

$P_1V_1=P_2V_2$

Where, $P_1$ is initial pressure and $P_2$ is final pressure. Similarly, $V_1$ is initial volume and $V_2$ is final volume.

Let's plug in the values in the equation:

(537 torr)(5.30 L) = (255 torr)( $V_2$ )

$V_2=(\frac{537 torr*5.30 L}{255 torr})$

$V_2$ = 11.2 L

So, the new volume of the container needs to be 11.2 L.

4 0

2 years ago