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AysviL [449]
2 years ago
12

The position of a train at a time 2 seconds is 100m from a station. Suppose its velocities at the end of 2 seconds and at the en

d of 10 seconds are 5m/s and 20m/s respectively. Find the position of the train at the end of 10 seconds.
Physics
1 answer:
Leni [432]2 years ago
8 0

vf²=vi²+2ad

5²=0+2a.100

a=0.125 m/s²

20²=0+2 x 0.125 x d

400 = 0.25d

d = 1600 m

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All Houston Methodist buildings system wide have an emergency power generator that turns on to supply emergency power after norm
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Answer:

D. 10 seconds

Explanation:

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Due to it being used in a hospital the importance of this emergency power system cannot be overemphasized as it is used to provide power supply to hospital equipment such as life support machines etc.

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two soccer players are running for the same ball during a game. Without looking the two collide. One player has a mass of 45 kg
jeka57 [31]

Well yuh see I dont got a clue

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4 years ago
A photographer uses his camera, whose lens has a 50 mm focal length, to focus on an object 2.5 m away. He then wants to take a p
Temka [501]

Answer:

0.004 m away from the film

Explanation:

u = Object distance

v = Image distance

f = Focal length = 50 mm

\frac{1}{f}=\frac{1}{u}+\frac{1}{v}\\\Rightarrow \frac{1}{f}-\frac{1}{u}=\frac{1}{v}\\\Rightarrow \frac{1}{v}=\frac{1}{0.05}-\frac{1}{2.5}\\\Rightarrow \frac{1}{v}=\frac{98}{5} \\\Rightarrow v=\frac{5}{98}=0.051\ m

The image distance is 0.051 m

When u = 50 cm

\frac{1}{f}=\frac{1}{u}+\frac{1}{v}\\\Rightarrow \frac{1}{f}-\frac{1}{u}=\frac{1}{v}\\\Rightarrow \frac{1}{v}=\frac{1}{0.05}-\frac{1}{0.5}\\\Rightarrow \frac{1}{v}=18\\\Rightarrow v=\frac{1}{18}=0.055\ m

The image distance is 0.055 m

The lens has moved 0.055-0.051 = 0.004 m away from the film

3 0
3 years ago
Are fat fish more likely to have broad stripes than thin fish?
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Novosadov [1.4K]

Answer:

an inverse relationship

7 0
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