The range of frequencies of visible light in a vacuum is mathematically given as
Fmin=4.19*10^14Hz to Fmax=1*10^15Hz
<h3>What is the range of frequencies of visible light in a vacuum?</h3>
Question Parameters:
The wavelengths of visible light vary from about 300 nm to 700 nm.
Generally, the equation for the frequency is mathematically given as
F=C/\lambda
Therefore
For Fmax
Fmax=1*10^15Hz
Where
Fmin=4.19*10^14Hz
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Answer:
Explanation: From 13:30 to 15:00, it past: 1 h 30 mins = 1.5
Then, the distance covered by Peter: 40x1.5= 60 miles
From 13:45 to 15:00, it pasts; 1 h 15min =1.25
Then, the distance covered by Philip. 30 x 1.25 = 37.5 miles
Lastly, the distance between them: 60-37.5= 22.5 miles
So the answer is 22.5
Answer:
Explanation:
The electronic configuration of many ions is that if a closes noble gas to them in a periodic table.
An Anion is a ion that has gained one or more electron, acquiring a negative charge.
A Cation is a ion that has lost one or more electron, gaining a positive charge.
Answer:
Given:
Temperature, T = 3.13 K
molar mass of molecular hydrogen, m = 2.02 g/mol = 
Solution:
To calculate the root mean squarer or rms speed of hydrogen molecule, we use the given formula:
where
R = rydberg's constant = 8.314 J/mol-K
Putting the values in the above formula:
Answer: 3.75 m
Explanation:
5 squirts in 1 second
So, 1 squirt in 1/5 second which is 0.2 second.
The difference in timing of two consecutive squirt is 0.2 second, so
time (t) = 0.2 s.
speed (s) = 15 m/s
Distance of separation (d) = ?
Now, formula for distance is
d = s × t
d = 15 × 0.2
d = 3.75 m
