Answer:
8.08 x 10^-5 m
Explanation:
A = 2 mm^2 = 2 x 10^-6 m^2
Total number of electrons, N = 9.4 x 10^18
time, t = 3 s
n = 5.8 x 10^28 electrons/ m^3
Current, i = Q / t = N x e / t = (9.4 x 10^18 x 1.6 x 10^-19) / 3 = 0.5 A
Let vd be the drift velocity.
i = n e A vd
0.5 = 5.8 x 10^28 x 1.6 x 10^-19 x 2 x 10^-6 x vd
vd = 2.7 x 10^-5 m/s
Distance traveled by the electrons = velocity x time
= vd x t = 2.7 x 10^-5 x 3 = 8.08 x 10^-5 m
Answer:
VB − VA = g tAB & (VA + VB)/2 = h / tAB
Explanation:
s = h = Displacement
tAB = t = Time taken
VA = u = Initial velocity
VB = v = Final velocity
a = g = Acceleration due to gravity = 9.8 m/s²
Hence, the equations VB − VA = g tAB & (VA + VB)/2 = h / tAB will be used
We use the following expression
T = 2*pi *sqrt(l/g)
Where T is the period of the pendulum
l is the length of the pendulum
and g the acceleration of gravity
We solve for l
l = [T/2*pi]² *g = [30s/2*pi]²* 9.8 [m/s²] = 223.413 m
The tower would need to be at least 223.413 m high
Infrared is created by detecting the produced radiation coming off of clouds. The temperature of the cloud will define the wavelength of radiation produced from the cloud. The benefit of the infrared imagery is that can be used day and night to conclude the temperature of the cloud tops and earth surface structures and to get the general idea of how clouds are. Based on the general guidelines to define cloud features, if the cloud is bright white on infrared then it is a high cloud or has a cloud top that is developed high into the troposphere. In this way infrared images actually display patterns of temperature on a gray scale such that at one extreme dark gray is warm and at the other extreme bright white is cold. A color scale is used to portray temperature and some improved infrared images show two or more gray scale sequences. High cold clouds are brighter white than low warm clouds.
Friction? For example, like when a car's tires skid on rough concrete.
