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stich3 [128]
2 years ago
12

Two figure skaters, one weighing 625 N and the other 725 N, push off against each other on frictionless ice. If the heavier skat

er travels at 1.5 m/s, how fast will the lighter one travel?
Physics
1 answer:
lora16 [44]2 years ago
3 0

The lighter one travel with the speed of 0.574 m/sec. Force is defined as the product of mass and acceleration. Its unit is Newton.

<h3>What is force?</h3>

Force is defined as the push or pull applied to the body. Sometimes it is used to change the shape, size, and direction of the body.

The two skaters push off against each other on frictionless ice, then torque act by the one skater on the other is equal.

P₁₂=P₂₁

F₁₂V₁ =F₂₁V₂

625 ×V₁= 725 N×  1.5 m/s

V₁=0.574 m/sec

Hence, the lighter one travel with the speed of 0.574 m/sec.

To learn more about the force, refer to the link;

brainly.com/question/26115859

#SPJ1

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How much energy is needed to heat and melt 3.0 kg of copper initially at 83°C?
Ne4ueva [31]

As we know that in order to melt the copper we need to take the temperature of copper to its melting point

So here heat required to raise the temperature of copper is given as

Q = ms\Delta T

We know that

melting temperature of copper = 1085 degree C

Specific heat capacity of copper = 385 J/kg C

now we have

Q = 3(385)(1085 - 83)

Q = 1157310 J

Q = 1157.3 kJ

now in order to melt the copper we know the heat required is

Q = mL

here we know that

L = 205 kJ/kg

now from above formula

Q = 3(205) kJ

Q = 615 kJ

now total heat required will be

Q = 1157.3 kJ + 615 kJ

Q = 1772.3 kJ

As we know that

1 Cal = 4.18 kJ

now we have

Q = \frac{1772.3}{4.18} = 430 KCal

6 0
3 years ago
At which point would most of the pendulum's potential energy have been transformed into kinetic energy?
Bess [88]

Answer:

C

Explanation:

i could be wrong but it seems the most logical

6 0
3 years ago
2 Points
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A wheel in the shape of a flat, heavy, uniform, solid disk is initially at rest at the top of an inclined plane of height 2.00 m
olasank [31]

Answer:

Explanation:

If friction is neglected, the wheel cannot roll and can only slide frictionlessly and will have the same velocity at the bottom of the ramp as if it had been in free fall as it has converted the same amount of potential energy.

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v = √(2gh) = √(2(9.81)(2.00)) = 6.26418... = 6.26 m/s

However if we do not ignore all friction and the wheel rolls without slipping down the slope, the potential energy becomes linear and rotational kinetic energy

mgh = ½mv² + ½Iω²

mgh = ½mv² + ½(½mR²)(v/R)²

2gh = v² + ½v²

2gh = 3v²/2

v = √(4gh/3) =√(4(9.81)(2.00)/3) = 5.11468... = 5.11 m/s

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A conversion factor is a ratio with a value of
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