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Marta_Voda [28]
2 years ago
12

What energy is required to move from Ca+ to Ca2+ + e−?

Chemistry
1 answer:
nataly862011 [7]2 years ago
4 0

Second Ionization energy is required to move from  Ca⁺ to Ca²⁺ + e⁻. Hence, option D is correct.

<h3>What is first ionization energy?</h3>

First ionization energy: The energy needed to remove the outermost, or highest energy, an electron from a neutral atom in the gas phase.

An element's second ionization energy is the energy required to remove the outermost, or least bound, an electron from a 1+ ion of the element. Because positive charge binds electrons more strongly, the second ionization energy of an element is always higher than the first.

Let us write the reaction equation properly:

                 Ca⁺ → Ca²⁺ + e⁻

In the reaction above, we see that calcium goes from a single charge to being doubly charged by losing an electron.

Different atoms bind their valence electrons with different amounts of energy. We must supply enough energy to remove the most loosely held electrons in an atom. This amount of energy required is called ionization energy.

The first ionization energy removes the outermost electron and makes the atom to become an ion.

Hence, option D is correct.

Learn more about the ionization energy here:

brainly.com/question/16243729

#SPJ1

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PIT_PIT [208]
CH₄(g) + 3 Cl₂(g) → CHCl₃(g) + 3 HCl(g)
From the equation we notice that 1 mole of methane produces 1 mole of chloroform:
16 g Methane → 119.38 g Chloroform
?   g Methane → 37.5 g Chloroform
by cross multiplication:
= (16 * 37.5) / 119.38 = 5.0 g methane
4 0
3 years ago
How does carbon dioxide behave differently (its properties) as a gas compared with as a solid?
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Hope this helped :)
6 0
2 years ago
If it takes 38.70cm of 1.90M NaOH to neutralize 10.30cm of H2SO4 in a battery, what is the molarity of H2SO4?
slamgirl [31]

Answer:

The molarity of the acid, H₂SO₄ is 3.57 M

Explanation:

We'll begin by writing the balanced equation for the reaction. This is illustrated below:

H₂SO₄ + 2NaOH —> Na₂SO₄ + 2H₂O

From the balanced equation above,

Mole ratio of the acid, H₂SO₄ (nₐ) = 1

Mole ratio of the base, NaOH (n₆) = 2

Finally, we shall determine the molarity of the acid, H₂SO₄. This can be obtained as follow:

Volume of base, NaOH (V₆) = 38.70 cm³

Molarity of base, NaOH (M₆) = 1.90M

Volume of acid, H₂SO₄ (Vₐ) = 10.30 cm³

Molarity of acid, H₂SO₄ (Mₐ) =?

MₐVₐ / M₆V₆ = nₐ/n₆

Mₐ × 10.3 / 1.9 × 38.70 = 1/2

Mₐ × 10.3 / 73.53 = 1/2

Cross multiply

Mₐ × 10.3 × 2 = 73.53 × 1

Mₐ × 20.6 = 73.53

Divide both side by 20.6

Mₐ = 73.53 / 20.6

Mₐ = 3.57 M

Thus, the molarity of the acid, H₂SO₄ is 3.57 M

8 0
3 years ago
Magnesium has 2 valence electrons, and oxygen has 6 valence electrons. Which type of bonding is likely to occur between a magnes
ra1l [238]

Magnesium will give two electrons to oxygen and both will become ions.

6 0
3 years ago
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