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Marta_Voda [28]
2 years ago
12

What energy is required to move from Ca+ to Ca2+ + e−?

Chemistry
1 answer:
nataly862011 [7]2 years ago
4 0

Second Ionization energy is required to move from  Ca⁺ to Ca²⁺ + e⁻. Hence, option D is correct.

<h3>What is first ionization energy?</h3>

First ionization energy: The energy needed to remove the outermost, or highest energy, an electron from a neutral atom in the gas phase.

An element's second ionization energy is the energy required to remove the outermost, or least bound, an electron from a 1+ ion of the element. Because positive charge binds electrons more strongly, the second ionization energy of an element is always higher than the first.

Let us write the reaction equation properly:

                 Ca⁺ → Ca²⁺ + e⁻

In the reaction above, we see that calcium goes from a single charge to being doubly charged by losing an electron.

Different atoms bind their valence electrons with different amounts of energy. We must supply enough energy to remove the most loosely held electrons in an atom. This amount of energy required is called ionization energy.

The first ionization energy removes the outermost electron and makes the atom to become an ion.

Hence, option D is correct.

Learn more about the ionization energy here:

brainly.com/question/16243729

#SPJ1

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12. A helium-filled weather balloon has a volume of 2.4 x 102 L at 99 kPa pressure and a
Luba_88 [7]

Answer:

The answer to your question is 8.74 g of He

Explanation:

Data

V = 2.4 x 10² L

P = 99 kPa

T = 0°C

mass = ?

Process

1.- Convert kPa to atm

P = 99 kPa = 99000 Pa

                   1 atm --------------- 101325 Pa

                    x       ---------------   99000 Pa

                   x = (99000 x 1) / 101325

                   x = 0.977 atm

2.- Convert temperature to °K

°K = 273 + 0

°K = 273

3.- Substitution

      PV = nRT

- Solve for n

      n = PV / RT

      n = (0.977)(2.4 x 10²) / (0.082)(273)

      n = 24.48 / 22.386

      n = 1.093 moles

4.- Calculate the grams of He

          8 g -------------------- 1 mol

           x    -------------------- 1.093 moles

           x = (1.093 x 8) / 1

           x = 8.74 g                      

6 0
3 years ago
Read 2 more answers
Why is pure silicon a poor conductor at room temperature brainly
trapecia [35]
Pure silicon is a poor conductor at room temperature because it has 4 valence electrons
4 0
3 years ago
The equilibrium constant is given for two of the reactions below. Determine the value of the missing equilibrium constant. 2A(g)
monitta

Answer:

The value of the missing equilibrium constant ( of the first equation) is 1.72

Explanation:

First equation: 2A + B ↔ A2B   Kc = TO BE DETERMINED

 ⇒ The equilibrium expression for this equation is written as: [A2B]/[A]²[B]

Second equation: A2B + B ↔ A2B2   Kc= 16.4

⇒ The equilibrium expression is written as: [A2B2]/[A2B][B]

Third equation:  2A + 2B ↔ A2B2     Kc = 28.2

⇒ The equilibrium expression is written as: [A2B2]/ [A]²[B]²

If we add the first to the second equation

2A + B + B ↔ A2B2   the equilibrium constant Kc will be X(16.4)

But the sum of these 2 equations, is the same as the third equation ( 2A + 2B ↔ A2B2)   with Kc = 28.2

So this means: 28.2 = X(16.4)

or X = 28.2/16.4

X = 1.72

with X = Kc of the first equation

The value of the missing equilibrium constant ( of the first equation) is 1.72

7 0
3 years ago
8. What is the % weight of Nickel in Nickel Sulfamate (Ni(SO3NH2)2) ?​
uranmaximum [27]

Answer:

% weight of nickle = 24 %

Explanation:

molar mass of Nickel Sulfamate (Ni(SO₃NH₂)₂) = 250.87 g/mol

Solution

1st we write down the molar mass of Ni

molar mass of Ni = 59 g/mol

now we write down the number of moles of Ni in (Ni(SO₃NH₂)₂)

number of moles of Ni = 1 mol

Now we calculate the mass of nickle present in (Ni(SO₃NH₂)₂)

<em>         mass = moles × molar mass</em>

mass = 1 mol × 59 g/mol

mass = 59 g

now we calculate the % weight of nickle in (Ni(SO₃NH₂)₂)

<em>       % weight = (weight of element ÷ total weight) × 100</em>

% weight of nickle = (59 ÷ 250.87) × 100

% weight of nickle = 0.24 × 100

% weight of nickle = 24 %

7 0
3 years ago
1.00-degree increase on the Celsius scale is equivalent to a 1.80-degree increase on the Fahrenheit scale. The temperature of a
castortr0y [4]
48.0°C×1.80 = 86.4°F
6 0
2 years ago
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