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egoroff_w [7]
3 years ago
10

8. What is the % weight of Nickel in Nickel Sulfamate (Ni(SO3NH2)2) ?​

Chemistry
1 answer:
uranmaximum [27]3 years ago
7 0

Answer:

% weight of nickle = 24 %

Explanation:

molar mass of Nickel Sulfamate (Ni(SO₃NH₂)₂) = 250.87 g/mol

Solution

1st we write down the molar mass of Ni

molar mass of Ni = 59 g/mol

now we write down the number of moles of Ni in (Ni(SO₃NH₂)₂)

number of moles of Ni = 1 mol

Now we calculate the mass of nickle present in (Ni(SO₃NH₂)₂)

<em>         mass = moles × molar mass</em>

mass = 1 mol × 59 g/mol

mass = 59 g

now we calculate the % weight of nickle in (Ni(SO₃NH₂)₂)

<em>       % weight = (weight of element ÷ total weight) × 100</em>

% weight of nickle = (59 ÷ 250.87) × 100

% weight of nickle = 0.24 × 100

% weight of nickle = 24 %

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Explanation:

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In this case, since the undergoing chemical reaction suggests that two moles of A react with one moles of B to produce two moles of C, for the final pressure we can write:

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