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Katarina [22]
3 years ago
9

According to Manor, the example of the subway train in New York City is an example of which type of uniqueness?

Engineering
1 answer:
Anuta_ua [19.1K]3 years ago
5 0

Answer:

(D) Uniquely Cheap

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Zarrin [17]

Answer:Even though EPA regulates and sets standards for public drinking water, many Americans use a home water treatment unit to: Remove specific contaminants. Take extra precautions because a household member has a compromised immune system. Improve the taste of drinking water.

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3 years ago
A heating torch is usually referred to as what?<br><br> Stick<br> Flower<br> Rose-bud<br> Lighter
Aleonysh [2.5K]
I would select rose-bud.
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Mike is involved in developing the model building codes that various states and local authorities in the United States adopt. He
Lyrx [107]
<h3>Answer:</h3>

Mike is involved in developing the model building codes that various states and local authorities in the United States adopt. He works with the <u>Workers</u> , which consists of members who are building code officials and building safety professionals.

8 0
3 years ago
Nitrogen gas is compressed at steady state from a pressure of 14.2 psi and a temperature 60o F to a pressure of 120 psi and a te
brilliants [131]

Answer:

a) 229.4281 hp.

b) 262.15 ft3/min.

Explanation:

Given data:

P1 = 14.2 psi

T1 = 60°F = 520° R

P2 = 120 psi

T2 = 500°F = 960° R

volumetric flow rate ( Av1 ) = 1200 ft^3 /min = 20 ft^3 / sec

attached below is the detailed solution

5 0
3 years ago
A rigid tank contains an ideal gas at 40°C that is being stirred by a paddle wheel. The paddle wheel does 240 kJ of work on the
Sergeu [11.5K]

To solve the problem it is necessary to consider the concepts and formulas related to the change of ideal gas entropy.

By definition the entropy change would be defined as

\Delta S = C_p ln(\frac{T_2}{T_1})-Rln(\frac{P_2}{P_1})

Using the Boyle equation we have

\Delta S = C_p ln(\frac{T_2}{T_1})-Rln(\frac{v_1T_2}{v_2T_1})

Where,

C_p = Specific heat at constant pressure

T_1= Initial temperature of gas

T_2= Final temprature of gas

R = Universal gas constant

v_1= Initial specific Volume of gas

v_2= Final specific volume of gas

According to the statement, it is an isothermal process and the tank is therefore rigid

T_1 = T_2, v_2=v_1

The equation would turn out as

\Delta S = C_p ln1-ln1

<em>Therefore the entropy change of the ideal gas is 0</em>

Into the surroundings we have that

\Delta S = \frac{Q}{T}

Where,

Q = Heat Exchange

T = Temperature in the surrounding

Replacing with our values we have that

\Delta S = \frac{230kJ}{(30+273)K}

\Delta S = 0.76 kJ/K

<em>Therefore the increase of entropy into the surroundings is 0.76kJ/K</em>

8 0
3 years ago
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