A specimen of commercially pure copper has a strength of 240 MPa. Estimate its average grain diameter using the Hall-Petch equat
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Answer:
Final mass of Argon= 2.46 kg
Explanation:
Initial mass of Argon gas ( M1 ) = 4 kg
P1 = 450 kPa
T1 = 30°C = 303 K
P2 = 200 kPa
k ( specific heat ratio of Argon ) = 1.667
assuming a reversible adiabatic process
<u>Calculate the value of the M2 </u>
Applying ideal gas equation ( PV = mRT )
P₁V / P₂V = m₁ RT₁ / m₂ RT₂
hence : m2 = P₂T₁ / P₁T₂ * m₁
= (200 * 303 ) / (450 * 219 ) * 4
= 2.46 kg
<em>Note: Calculation for T2 is attached below</em>
Answer:
The resistance is 24.9 Ω
Explanation:
The resistivity is equal to:
The area is:
A = 60 * 60 = 3600 um² = 0.36x10⁻⁴cm²
If NA is greater, then, the term 1/NA can be neglected, thus the equation:
Where
V = 0.44 V
E = 11.68*8.85x10¹⁴ f/cm
The length is:
L = 10 - 0.335 = 9.665 um
The resistance is: