it is proposed to use a small waterfall to turn an electricity generator. 10 meter cube of water fall 50m per minute. only one-f

Question

2 years ago

11

ifth of its energy can be obtained usefully

1 answer:

nirvana33 [79] · Answer 1 · 2023-02-08T04:12:56+03:00

This question is related to density where 16.7 kW power is used.

<h3>What is Density?</h3>

Density is defined as mas per unit volume. It is denoted by ρ

We know the density of water is 1000kg/m³.

The given volume is 10m³. we have to find the mass. i.e. 10000 kg.

We know that $Density =\frac{mass}{Volume}$

Mass = Density x Volume

Mass = 1000kg/ m³ x 10m³ = 10000kg.

Here, We know that work against gravity is mgh.

So, 10000 kg x 10 m/s² x 50m = 5000000J.

But only one fifth of its energy is used.

5000000 / 5 = 1000000

Now we have the work done and time, so lets solve power.

Power=work done /time

1000000/60sec.

Power =16666.67 or 16.7kW

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