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Molodets [167]
3 years ago
13

What's the size of a astatine Atom compared to a tellurium Atom

Chemistry
1 answer:
Lena [83]3 years ago
7 0
                         the answer is <span>Astatine is one period further than tellurium, meaning it has an extra shell. Therefore, the At atom will be bigger than the Te atom. </span>
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If the density of gold is 19.3 g/cm3 what would be the volume of 550 g of gold?​
RUDIKE [14]

Answer:

28.497 cm3

Explanation:

Formula

D=m/v

Given data:

density = 19.3g/cm3

mass = 550 g

Now we will put the values in formula:

V=m/d

V=550 g/ 19.3 g/cm3  = 28.497 cm3

So the volume of gold is 28.497 cm3.

7 0
4 years ago
A chemist weighed out 19.9 g of aluminum. Calculate the number of moles of aluminum she weighed out.
vodomira [7]
Aluminum is 26.982 grams per mole, so 26.982/19.9 will give you the moles 1.3558794
3 0
4 years ago
How many additional electrons can fit into the n=3 shell of sulfur
Sever21 [200]
2. <span>(Note that sulfur is 2 columns from the right-hand end of the periodic table)</span>
8 0
3 years ago
Problem Page Predict the reactants of this chemical reaction. That is, fill in the left side of the chemical equation. Be sure t
Helga [31]

Answer:

CaCl2 + H2O  Ca2+(aq) + 2Cl-(aq)

Explanation:

CaCl2 + H2O  Ca2+(aq) + 2Cl-(aq)

When CaCl2 is dissolved in H2O (water) it will dissociate (dissolve) into Ca+2 and Cl- ions.

The dissolution of calcium chloride is an exothermic process.  

6 0
3 years ago
1. Imagine you have a sealed 20.0 L balloon filled with helium gas at 750 mmHg in the
SVETLANKA909090 [29]

Answer:

17.6510 L

Explanation:

First we should get the number of moles of helium here by Boyle's law

PV=nRT

P=750/760= 0.9868 atm

T=25+273=298 kelvin

R= 0.08206

V= 20L

so

n=PV/RT

n=0.9868×20/0.08206×298

n=0.80707 mol

Then use the same law

V=0.80707×0.08206×263/0.9869=

17.6510L

SO THE VOLUME WILL BE 17.6510 L

6 0
2 years ago
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