2 years ago

Which buffer can be suitable to prepare a solution that needs to be buffered at ph 4?

Chemistry

1 answer:

zlopas [31]2 years ago

4 0

Answer:

For pH= 4.00 :

Add 0.1 ml of 0.1 molar NaOH to 50 ml of 0.1 molar potassium hydrogen phthalate .

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A chemistry student needs of acetone for an experiment. By consulting the CRC Handbook of Chemistry and Physics, the student dis

galben [10]

Answer:

The answer is " $7.90 \ g$ ".

Explanation:

Please finds the complete question in the attached file.

$Volume = 10.0 \ mL \\\\Density =0.79 g\ cm^3$

$\text{Density}=\frac{Mass}{Volume}$

$Mass = Density \times Volume$

$=(0.790 g\ cm^3) \times 10.0 \ mL\\\\=7.90 \ g$

The mass of acetone to be weighed is $7.90 \ g$

8 0

2 years ago

fill in the blank: 1.)the amount of space that matter fills is its.................. 2.)a state of matter with a definite volume

marshall27 [118]

1) mass

2) gas

3) liquid

4) temperature

5) pressure

8 0

3 years ago

Read 2 more answers

Energy conversion means reducing energy use True or false

I am Lyosha [343]

False, energy conversion just means the energy is going to be used by another force

3 0

3 years ago

when carbon is burned in the air, it reacts with oxygen to form carbon dioxide. when 22.8 g of carbon were burned in the presenc

OverLord2011 [107]

Answer:

So there is83.6g CO2 produced

Explanation:

Burning carbon with air has the following equation

C + O2 → CO2

For 1 mol Carbon, we have 1 mol O2 and 1 mol CO2

Step 2: Calculating moles

mole C = 22.8g / 12g/mole

Mole C = 1.9 mole

1.9 mole C will completely react

Since for each mole C there is 1 mole O2 and 1 mole CO2

This means there will also react 1.9 mole of 02, to be formed 1.9 mole of CO2

mole CO2 = mass CO2 / Molar mass CO2

mass CO2 = 1.9 mole CO2 * 44g/mole =<u>83.6g CO2</u>

In this reaction 18.2 g of O2 remained unreacted

we can control this: 79g - 18.2 g = 60.8g

1.9 mole * 32g/mol = 60.8g

So there is83.6g CO2 produced

4 0

3 years ago

Olive oil has a density of 0.92 g/mL. How much would 1 liter of olive oil weigh in grams?

svp [43]

Dimension analysis is to be used to solve this problem. First convert 1L to milliliters. That is equivalent to 1000 ml. Then by dimension analysis, multiply the volume ( 1000ml) to the density of oil (0.92 g/ml) resulting to the answer: 920 grams.

4 0

3 years ago