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torisob [31]
1 year ago
5

How many grams of water at 25 C must be mixed in an insulated container with 250 grams of water at 93 C if the final temperature

of the combined water is to be 75 C.
Chemistry
1 answer:
nydimaria [60]1 year ago
7 0

Answer:

Explanation

Comment

Normally you would just use m*c*delta T. But the c is the same in both cases, so you need just use m*deltaT

Givens

25 degrees

m = ?

T = 25

t = final temp = 75

93 degrees

m = 250

T = 93

t = final temp = 75

Solution

(t - 25)*m = (93 - t) * 250                   Remove the brackets

75*m - 25m = 93*250 -  250*75      Combine the right

m(75 - 25) = 23250 - 250*75

50 m = 23250 - 18750                      Combine

50 m = 4500                                      Divide both sides by 50

50*m/50 = 4500/50

m = 90

Answer: 90 grams are needed.

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Schach [20]

Answer:

2.74 M

Explanation:

Given data:

Mass of sodium chloride = 80.0 g

Volume of water = 500.0 mL

Molarity of solution = ?

Solution:

Molarity is used to describe the concentration of solution. It tells how many moles are dissolve in per litter of solution.

Formula:

Molarity = number of moles of solute / L of solution

Now we will convert the mL into L.

500.0 mL× 1 L /1000 mL =  0.5 L

In next step we will calculate the number of moles of sodium chloride.

Number of moles = mass/molar mass

Number of moles = 80.0 g/ 58.4 g/mol

Number of moles = 1.37 mol

Molarity:

M =  1.37 mol/ 0.5 L

M =  2.74 M

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