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horsena [70]
2 years ago
12

Two point particles, with the same charge, are located at two vertices of an equilateral triangle. A third charged particle is p

laced so the electric field at the third vertex is zero. The third particle must:
Physics
1 answer:
Mama L [17]2 years ago
3 0

The third particle must be placed at the perpendicular bisector of the line joining the first two charges.

<h3>What is electric field?</h3>

The field developed when a charge is moved. In this field, a charge experiences an electrostatic force of attraction or repulsion depending on the nature of charge.

Given, two point particles, with the same charge, are located at two vertices of an equilateral triangle. A third charged particle is placed so the electric field at the third vertex is zero.

The electric field must exert the net electrostatic force equal to zero.

For this, third charge should be placed at the perpendicular bisector of the line joining the first two charges.

Thus, the third particle must be placed at the perpendicular bisector of the line joining the first two charges.

Learn more about electric field.

brainly.com/question/15800304

#SPJ1

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Instantaneous speed is measured
torisob [31]
By using a tangent line.

I need a bit more info to be sure but that's not wrong.
6 0
3 years ago
As a fish jumps vertically out of the water, assume that only two significant forces act on it: an upward force exerted by the t
vodomira [7]

Complete Question:

As a fish jumps vertically out of the water, assume that only two significant forces act on it: an upward force F exerted by the tail fin and the downward force due to gravity. A record Chinook salmon has a length of 1.50 m and a mass of 48.0 kg. If this fish is moving upward at 3.00 m/s as its head first breaks the surface and has an upward speed of 6.30 m/s after two-thirds of its length has left the surface, assume constant acceleration and determine the following. (a) the salmon's acceleration m/s2 upward (b) the magnitude of the force F during this interval N

Answer:

(a) acceleration = 15.3 ms⁻²

(b) Magnitude of net force = 734.4 N

Magnitude of upward force exerted by tail fin = 1204.8 N

Explanation:

Mass of the salmon fish = 48 kg

Length of the Salmon Fish = 1.5 m

g = 9.8 ms⁻²

(a) salmon's acceleration during the time interval N:

Downward Force on the fish is equal to the Force due to gravity and is given as:

F₂ = mg

= 48 * 9.8

= 470.4 N

The direction of movement of the fish is upward and the acceleration is constant. We are given two different velocities of fish at two different instances.

- When the head breaks out of the water surface first:

Initial velocity = v₁ = 3 m/s

- When two third of its body length is out = d = 1 m

 Final Velocity = v₂ = 6.3 m/s

Using the third equation of motion:

2*a*d = v₂² - v₁²

a = (6.3² - 3²)/2*1

a = 15.3 ms⁻²

(b) magnitude of force F during this interval N = ?

We are assuming that F is the net force consisting of both the upward and the downward force.

According to Newton's 2nd law of motion, Force is given as:

F = ma

F = 48 kg * 15.3

F = 734.4 N

Magnitude of upward Force = Fₓ

Force Fₓ exerted by the tail fin of the fish is given by

F = Fₓ - F₂

That is the net force is the sum of the upward and downward forces acting on the fish body. Fₓ is positive because it is in upward direction and F₂ is negative because it is in downward direction. F which is the net force here is positive as Fₓ > F₂.

=>   Fₓ = F + F₂

Fₓ = 734.4 + 470.4

Fₓ = 1204.8 N

7 0
4 years ago
What are two ways in which all types of precipitation are alike
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Answer:

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Explanation:

6 0
3 years ago
Two lab carts are pushed together with a spring mechanism compressed between them. Upon release, the 5.0 kg cart repels one way
JulijaS [17]

Answer:

V = -0.3 m/sec.

Explanation:

5.0 x 0.12 + 2.0 x v = 0. Which means that V = -0.3 m/sec.

The -ve sign shows it moves in the opposite direction.

8 0
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