The quotient of 8.4x10° and a number n results in 5.6x 1027. What is the value of n?

PLZ HELP WILL GIVE BRAINLIEST

xxTIMURxx [149]

Answer:

12.7m/s

Explanation:

Given parameters:

Mass of the diver = 77kg

Height = 8.18m

Unknown:

Final velocity = ?

Solution:

To solve this problem, we use one of the motion equations.

v² = u² + 2gh

v is the final velocity

u is the initial velocity

g is the acceleration due to gravity

h is the height

v² = 0² + (2 x 9.8 x 8.18)

v² = 160.3

v = 12.7m/s

7 0

3 years ago

A bag of groceries is on the back seat of your car as you stop for a stop light. The bag does not slide. Apply your analysis to

Romashka [77]

Answer:

This can be the FBD of the bag.

(my bag looks more like a box tho ^^")

7 0

2 years ago

Two satellites are in circular orbits around the earth. The orbit for satellite A is at a height of 403 km above the earth’s sur

BARSIC [14]

Answer:

$v_A=7667m/s\\\\v_B=7487m/s$

Explanation:

The gravitational force exerted on the satellites is given by the Newton's Law of Universal Gravitation:

$F_g=\frac{GMm}{R^{2} }$

Where M is the mass of the earth, m is the mass of a satellite, R the radius of its orbit and G is the gravitational constant.

Also, we know that the centripetal force of an object describing a circular motion is given by:

$F_c=m\frac{v^{2}}{R}$

Where m is the mass of the object, v is its speed and R is its distance to the center of the circle.

Then, since the gravitational force is the centripetal force in this case, we can equalize the two expressions and solve for v:

$\frac{GMm}{R^2}=m\frac{v^2}{R}\\ \\\implies v=\sqrt{\frac{GM}{R}}$

Finally, we plug in the values for G (6.67*10^-11Nm^2/kg^2), M (5.97*10^24kg) and R for each satellite. Take in account that R is the radius of the orbit, not the distance to the planet's surface. So $R_A=6774km=6.774*10^6m$ and $R_B=7103km=7.103*10^6m$ (Since $R_{earth}=6371km$ ). Then, we get:

$v_A=\sqrt{\frac{(6.67*10^{-11}Nm^2/kg^2)(5.97*10^{24}kg)}{6.774*10^6m} }=7667m/s\\\\v_B=\sqrt{\frac{(6.67*10^{-11}Nm^2/kg^2)(5.97*10^{24}kg)}{7.103*10^6m} }=7487m/s$

In words, the orbital speed for satellite A is 7667m/s (a) and for satellite B is 7487m/s (b).

7 0

2 years ago

PLEAS HELP.

koban [17]

<span>A: put an atom on a poster in the exhibit
   Good luck. The poster itself is made of trillions of trillions of trillions
   of atoms. You could not see the extra one any easier than you could
   see the ones that are already there, and even if you could, it would be
   lost in the crowd.

B: use a life size drawing of an atom
   Good luck. Nobody has ever seen an atom. Atoms are too small
   to see. That's a big part of the reason that nobody knew they exist
   until less than 200 years ago.

D: set up a microscope so that visitors can view atoms
   Good luck. Atoms are way too small to see with a microscope.

</span><span><span>C: Display a large three dimensional model of an atom.
  </span> </span>Finally ! A suggestion that makes sense.
   If something is too big or too small to see, show a model of it
   that's just the right size to see.

8 0

2 years ago

1. It is an object's tendency to resist a change in motion.

IRISSAK [1]

<h2>ANSWER</h2>

Inertia
Astronomy

#CarryOnLearning

6 0

2 years ago