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svetoff [14.1K]
2 years ago
15

What's the real power of a purely resistive circuit in which the RMS voltage measures 80 volts and the RMS current measures 5 am

ps?
A. 85 watts

B. 120 watts

C. 240 watts

D. 400 watts
Physics
1 answer:
Nat2105 [25]2 years ago
7 0

Answer:

D.400 watt

Explanation:

  • B/c <em>Pave</em><em>=</em><em>Irms</em><em>Vrms</em>
  • <em>Pave</em><em>=</em><em>(</em><em>5</em><em>)</em><em>(</em><em>8</em><em>0</em><em>)</em>
  • <em>Pave</em><em>=</em><em>4</em><em>0</em><em>0</em><em> </em><em>watt</em>

<em>where</em><em> </em><em>Pave</em><em> </em><em>=</em><em> </em><em>average</em><em> </em><em>power</em><em> </em>

<em>Irms</em><em>=</em><em>RMS</em><em> </em><em>current</em><em> </em><em>&</em>

<em>Vrms</em><em>=</em><em>RMS</em><em> </em><em>voltage</em>

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Car A has a mass of 1,000 kg and is traveling 60 km/hr. Car B has a mass of 2,000 kg and is traveling 30 km/hr. Compare the kine
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Answer:

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Explanation:

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here we know that

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so here we will have kinetic energy of Car A

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now we have kinetic energy of B is given as

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4 years ago
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. An aeroplane takes 30 min to travel from Biratnagar to Kathmandu. If the air distance between
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<u>Answer:</u>

average velocity = \bf 900 \space\ km/h

<u>Explanation:</u>

We can find the average velocity using the following equation:

\boxed{average \space\ velocity = \frac{total \space\ distance  \space\  travelled}{ \space\ time  \space\ taken}} .

In this case:

• total distance travelled = 450 km

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Substituting these values into the equation:

average \space\ velocity = \frac{450 \space\ km }{ 0.5 \space\ h}

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Answer:

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Explanation:

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So length of rectangle l = 0.7 m and width w = 0.35 m

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It is given that electric field is along the x axis

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