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Kamila [148]
2 years ago
12

Question 25 (Mandatory) (1 point)

Physics
1 answer:
snow_lady [41]2 years ago
4 0

It's very important for an individual to possess the ability to disagree respectfully with another person because strengthens one's relationships.

<h3>What is a conflict?</h3>

A conflict is any form of disagreement, misunderstanding, or struggle that arises between two (2) or more parties, especially due to any of the following reasons;

  • Differing opinions
  • Incompatibilities
  • A difficult challenge
  • Superiority

However, it's very important for an individual to possess the ability to disagree respectfully with another person because of the following:

  • Working through conflicts peacefully.
  • It strengthens one's relationships and understanding of others.
  • It mitigates the chances of physical confrontations and assaults.

Read more on conflict here: brainly.com/question/24769299

#SPJ1

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Answer:

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Explanation:

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One particle has a charge of -1.87 x 10-9 C, while another particle has a charge of -1.10 x 10-9 C. If the two particles are sep
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Suppose you increase your walking speed from 5 m/s to 14 m/s in a period of 3 s. What is your acceleration
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A crate rests on a flatbed truck which is initially traveling at 17.9 m/s on a level road. The driver applies the brakes and the
Mamont248 [21]

Answer:

The minimum coefficient of friction required is 0.35.  

Explanation:

The minimum coefficient of friction required to keep the crate from sliding can be found as follows:

-F_{f} + F = 0      

-F_{f} + ma = 0      

\mu mg = ma

\mu = \frac{a}{g}

Where:

μ: is the coefficient of friction

m: is the mass of the crate

g: is the gravity

a: is the acceleration of the truck

The acceleration of the truck can be found by using the following equation:

v_{f}^{2} = v_{0}^{2} + 2ad

a = \frac{v_{f}^{2} - v_{0}^{2}}{2d}

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d: is the distance traveled = 46.1 m

v_{f}: is the final speed of the truck = 0 (it stops)      

v_{0}: is the initial speed of the truck = 17.9 m/s

a = \frac{-(17.9 m/s)^{2}}{2*46.1 m} = -3.48 m/s^{2}        

If we take the reference system on the crate, the force will be positive since the crate will feel the movement in the positive direction.  

\mu = \frac{a}{g}  

\mu = \frac{3.48 m/s^{2}}{9.81 m/s^{2}}

\mu = 0.35

Therefore, the minimum coefficient of friction required is 0.35.  

I hope it helps you!

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Old Grandpy!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!


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