Answer:
7.5 × 10^9 J.
Explanation:
So, we are given the following data or parameters or information for the proper solving of the question above;
=> ''actual force exerted by the tractor beam as a function of position is given by F(x) = ax + , where a = 6.1 x 10 N/mº and B = -4.1 x 10° N''
=> " Assume the supply spacecraft had an initial kinetic energy of KE = 2.7 x 10" J "
=> "that the tractor beam force is applied on the spacecraft over a distance of 7.5 x 10^11 m away.from its beginning position at = 0.0 m"
So, we can then solve it as;
KE2 – KE1 = F(x) dr.
KE2 - 2.7 x 10^11 J = - 3.5 × 10^6 × 7.5 x 10^4.
KE2 = 7.5 × 10^9 J.
Answer:
a) i = -4.02 cm
, b) h’= 1,576 cm
Explanation:
a) The constructor equation is
1 / f = 1 / i + 1 / o
Where f is the focal length, i and o are the distance to the image and the object
Let's clear the distance to the image
1 / i = 1 / f - 1 / o
1 / i = 1 / -19 - 1 / 5.1
1 / i = 0.2487
i = -4.02 cm
b) let's use the expression of magnification
m = h’/ h = - i / o
h’= - h i / o
h’= 2.2 4.02 /5.1
h’= 1,576 cm
Answer:
1.53 g
Explanation:
Given,
Initial speed = 30 m/s
Final speed = 0 m/s
Period of stretch, t = 2 s
average deceleration = ?
we know
a = -15 m/s²
Deceleration of the jumper = 15 m/s²
Deceleration in terms of g
Hence, the deceleration of the jumper is equal to 1.53 g
By heat or change in matter,
there can be different reactions that create heat (like exothermic or endothermic reactions)
or movement can give off energy too,
energy is basically just heat
Answer:
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