Complete Question
Planet D has a semi-major axis = 60 AU and an orbital period of 18.164 days. A piece of rocky debris in space has a semi major axis of 45.0 AU. What is its orbital period?
Answer:
The value is
Explanation:
From the question we are told that
The semi - major axis of the rocky debris 
The semi - major axis of Planet D is 
The orbital period of planet D is 
Generally from Kepler third law

Here T is the orbital period while a is the semi major axis
So

=>
=> ![T_R = 18.164 * [\frac{ 45}{60} ]^{\frac{3}{2} }](https://tex.z-dn.net/?f=T_R%20%20%3D%2018.164%20%20%2A%20%20%5B%5Cfrac%7B%2045%7D%7B60%7D%20%5D%5E%7B%5Cfrac%7B3%7D%7B2%7D%20%7D)
=>
Answer:
C. Chemical energy
Explanation:
The different types of energy listed in this question are:
A) Electrical energy: it is the energy related to the flow of electrical charges (current)
B) Nuclear energy: it is the energy contained in the nuclei of the atoms, and released during nuclear reactions
C) Chemical energy: it is the energy contained in the bonds between molecules, and it is released during chemical reactions
D) Thermal energy: it is the energy associated with the motion of molecules
Photosynthesis is the process that plants use to transform the light energy (coming from the Sun) into chemical energy. In fact, in this process, plants absorb CO2 (from the atmosphere) and solar energy (from the light), and they convert them into sugars (glucose) and oxygen. Therefore, the initial energy coming as solar energy is converted into energy of the bonds of the molecules of glucose (so, chemical energy).
So, the correct option is C).
(20 miles) x ( 1/45 hour/mile) =
(20/45) (hour) = <em>
4/9 hour = </em>26 minutes 40 seconds