All categories

1 year ago

Alllura is running to the blue lion so she can join the others in forming voltron. if allura starts off

1 answer:

5 0

The acceleration will be 1.9166 m/s². According to Newton's second law, the eventual effect of all forces applied to a body is its acceleration.

<h3>What is acceleration?</h3>

The rate of change of velocity with respect to time is known as acceleration.

Given data:

u(Initial velocity)=2.50m/s

v(Final velocity)=8.25m/s

t(time period)= 3.00s

The acceleration of the Allura will be :

$\rm a = \frac{v-u}{t} \\\\ a= \frac{8.25-2.50 }{3.00 }\\\\ a= 1.9166 \ m/s^2$

Hence, the acceleration will be 1.9166 m/s².

To learn more about acceleration, refer to the link;

brainly.com/question/2437624

#SPJ1

You might be interested in

What is the mechanical advantage of a single pulley

Viktor [21]

the answer is 1 because a single pulley has 1 rope

5 0

2 years ago

Read 2 more answers

A uniform magnetic field is perpendicular to the plane of a circular loop of diameter 13 cm formed from wire of diameter 2.6 mm

I am Lyosha [343]

Answer:

Rate of change of magnetic field is $3.466\times 10^3T/sec$

Explanation:

We have given diameter of the circular loop is 13 cm = 0.13 m

So radius of the circular loop $r=\frac{0.13}{2}=0.065m$

Length of the circular loop $L=2\pi r=2\times 3.14\times 0.065=0.4082m$

Wire is made up of diameter of 2.6 mm

So radius $r=\frac{2.6}{2}=1.3mm=0.0013m$

Cross sectional area of wire $A=\pi r^2=3.14\times0.0013^2=5.30\times 10^{-6}m^2$

Resistivity of wire $\rho =2.18\times 10^{-8}m$

Resistance of wire $R=\frac{\rho L}{A}=\frac{2.18\times 10^{-8}\times 0.4082}{5.30\times 10^{-6}}=1.67\times 10^{-3}ohm$

Current is given i = 11 A

So emf $e=11\times 1.67\times 10^{-3}=0.0183volt$

Emf induced in the coil is $e=-\frac{d\Phi }{dt}=-A\frac{dB}{dt}$

$0.0183=5.30\times 10^{-6}\times \frac{dB}{dt}$

$\frac{dB}{dt}=3.466\times 10^3=T/sec$

8 0

2 years ago

At a distance of 11 cm from a presumably isotropic, radioactive source, a pair of students measure 65 cps (cps = counts per seco

Alborosie

To solve the problem, it is necessary the concepts related to the definition of area in a sphere, and the proportionality of the counts per second between the two distances.

The area with a certain radius and the number of counts per second is proportional to another with a greater or lesser radius, in other words,

$A_1*m=M*A_2$

$A_i =Area$

M,m = Counts per second

Our radios are given by

$r_1 = 11cm$

$R_2 = 20cm$

$m = 65cps$

Therefore replacing we have that,

$A_1*m=M*A_2$

$4\pi r_1^2*m = M * 4\pi R_2^2 M$

$r^2*m=MR^2$

$M = \frac{m*r^2}{R^2}$

$M = \frac{65*11^2}{20^2}$

$M = 19.6625cps$

Therefore the number of counts expect at a distance of 20 cm is 19.66cps

7 0

2 years ago

3) Ęplain why muddy water is<br> Heterogeneous<br> mixture

nataly862011 [7]

Answer:

muddy water is a heterogeneous mixture, which is Suspension.

7 0

2 years ago

Describe how to measure the internal diameter of a beaker using a Vernier caliper?

n200080 [17]

Answer:

Hope it helps..

Explanation:

Let n be the number of the vernier scale division which coincides with the main scale division. Rotate the vernier caliper 90° and repeat the steps 4 and 5 for measuring the internal diameter in perpendicular direction. To measure the depth, find the total reading and zero correction.

PLEASE MARK ME AS BRAINLIEST

3 0

2 years ago

Read 2 more answers