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torisob [31]
3 years ago
9

Calculate the freezing point (Kf = 1.86 °C/m) of a 2.1m aqueous solution of KCl.

Chemistry
1 answer:
Wittaler [7]3 years ago
7 0

Answer:

The freezing point of the solution is - 3.90 °C.

Explanation:

  • We can solve this problem using the relation:

<em>ΔTf = (Kf)(m),</em>

where, ΔTf is the depression in the freezing point.

Kf is the molal freezing point depression constant of water = - 1.86 °C/m,

m is the molality of the solution (m = 2.1 m).

<em>∴ ΔTf = (Kf)(m)</em> = (-1.86 °C/m)(2.1 m) =<em> - 3.90 °C.</em>

<em>∵ The freezing point if water is 0.0 °C and it is depressed by - 3.90 °C.</em>

<em>∴ The freezing point of the solution is - 3.90 °C.</em>

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